So Sahra is 3 times as old as her daugter. That means that the sum of their age is the daughters age times 4.
We can prove that by saying the daughters age is x. Sahra's age must be 3x. Their sum must be x+3x = 4x.
So to get the daughters age we divide the sum by 4, which is 8.
Answer:
810
Step-by-step explanation:
21 = 42
Decode:
Number in the tens place = 2 x 2 = 4
Number in the ones place = 1 x 2 = 2
Answer: 42
39 = 618
Decode:
Number in the tens place = 3 x 2 = 6
Number in the ones place = 9 x 2 = 18
Answer: 618
17 = 214
Decode:
Number in the tens place = 1 x 2 = 2
Number in the ones place = 7 x 2 = 14
Answer: 214
Find 45
Number in the tens place = 4 x 2 = 8
Number in the ones place = 5 x 2 = 10
Answer: 810
<span>you're given both arcs, minor and major, or near and far arcs, all you need to do, is really plug them in</span>
Answer:
v > -25/p
r = -5 +7/3 w
Step-by-step explanation:
- pv + 40 < 65
Subtract 40 from each side
- pv + 40-40 < 65-40
-pv < 25
Divide each side by -p (remember to flip the inequality since we are dividing by a negative)
-pv/-p > 25/-p
v > -25/p
7w - 3r = 15
Subtract 7w from each side
7w-7w - 3r = 15-7w
-3r = 15-7w
Divide by -3
-3r/-3 = (15-7w)/-3
r = -5 +7/3 w
Answer:
D.
Step-by-step explanation:
Remember that the limit definition of a derivative at a point is:
![\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28a%29%5D%3D%20%5Clim_%7Bx%20%5Cto%20a%7D%5Cfrac%7Bf%28x%29-f%28a%29%7D%7Bx-a%7D%7D)
Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:
![\displaystyle{\frac{d}{dx}[f(1)]= \lim_{x \to 1}\frac{\ln(x+1)-\ln(2)}{x-1}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%281%29%5D%3D%20%5Clim_%7Bx%20%5Cto%201%7D%5Cfrac%7B%5Cln%28x%2B1%29-%5Cln%282%29%7D%7Bx-1%7D%7D)
Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).
The answer will thus be D.
