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irinina [24]
3 years ago
15

Given the linear equation Ax+By=8,it's x intercept is (8,0) and y-intercept is (0,8). What are the values of a and b

Mathematics
1 answer:
enyata [817]3 years ago
3 0

Answer:

<em>A=1, B=1</em>

Step-by-step explanation:

<u>Equation of the line in intercept form </u>

The intercept form of the equation of a line is:

\displaystyle \frac{x}{h}+\frac{y}{k}=1

Where:

h = x-intercept

k = y-intercept

We are given the y-intercept (0,8) and x-intercept (8,0), thus the equation is:

\displaystyle \frac{x}{8}+\frac{y}{8}=1

Multiplying by 8:

x + y = 8

Thus, the values of A and B are:

A=1, B=1

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HELP PLEASE!!!!!!
wel

Pat's average rate of change over the entire trip up the mountain is 41.7, while the cable car's average rate of change over the entire trip up the mountain is 50

<h3>The average annual rate of change</h3>

The given parameters are:

Value in 1990 = $12,500

Value in 2009 = $20,050

The average annual rate of change is then calculated as:

Rate of change = Difference in the values/Difference in the years

So, we have:

Rate of change = (20050 - 12500)/(2009 - 1990)

Evaluate

Rate of change = 397.37

<h3>Pat and cable car</h3>

<u>The complete table of average rate of change</u>

The average rate of change is calculated as:

Average rate of change = Difference in heights at the intervals/Difference in the interval

So, we have:

<em>0 - 2 minutes</em>

Pat = (125 - 0)/(2 - 0) = 62.5

Cable = (100 - 0)/(2 - 0) = 50

<em>2 - 4 minutes</em>

Pat = (200 - 125)/(4 - 2) = 37.5

Cable = (200 - 100)/(4 - 2) = 50

<em>4 - 5 minutes</em>

Pat = (225 - 200)/(5 - 4) = 25

Cable = (250 - 200)/(5 - 4) = 50

So, the complete table is:

Time   0 - 2 minutes     2 - 4 minutes    4 - 5 minutes

Pat           62.5                     37.5                   25

Cable       50                         50                      50

<h3>Is the rate of change constant for Pat? Is it constant for the cable car? </h3>

The rate of change is not constant for Pat, while the rate of change is constant for the cable car

This is so because, we have different values for the rate of change for Pat, while we have only one value for the rate of change for Cable car

<h3>The average rate of change over the entire trip up the mountain</h3>

This is calculated as:

Average rate of change = Difference in heights at the intervals/Difference in the interval

So, we have:

Pat = (250 - 0)/(6 - 0) = 41.7

Cable = (250 - 0)/(5 - 0) = 50

Hence, Pat's average rate of change over the entire trip up the mountain is 41.7, while the cable car's average rate of change over the entire trip up the mountain is 50

Read more about average rate of change at

brainly.com/question/2170564

#SPJ1

6 0
2 years ago
Find the measure of BE step by step ​
Zigmanuir [339]

Answer:

BE = 49

Step-by-step explanation:

In triangle BDC

  65^2=56^2+BD^2

  65^2-56^2=BD^2

  4225-3136=BD^2

  1089=BD^2

   33=BD

In triangle FDE

    65^2=63^2+DE^2

    4225-3969=DE^2

    256 = DE^2

    16=DE

since ED+DB=BE

THEREFORE

      16+33=BE

         49=BE

6 0
3 years ago
Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i
dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s

Also,

v=r\omega

Where

\omega is the angular speed

So,

\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

8 0
4 years ago
An investment of P=1237.50 is compounded annually with a 6.75% APR . Find the value of the investment after 5 and a half years.
Ber [7]

Answer:

Under compound interest, not only does the principal generate interest, so does the previous accumulated interest. The future value F of P dollars compounded annually for t years with an annual percentage rate (APR) r expressed as a decimal is .

5 0
3 years ago
Read 2 more answers
find the curved surface area and total surface area of a right circular cylinder whose height is 15 cm and the radius of the bas
otez555 [7]

Answer:

CSA = 660cm^2 --- Curved Surface Area

TSA = 968cm^2  --- Total Surface Area

Step-by-step explanation:

Given

Shape: Cylinder

h = 15 -- height

r = 7 --- radius

Solving (a): The curved surface area (CSA)

This is calculated as:

CSA = 2\pi rh

This gives:

CSA = 2 * \frac{22}{7} * 7 * 15

CSA = 2 * 22* 15

CSA = 660cm^2

Solving (b): The total surface area (TSA)

This is calculated as:

TSA = 2\pi r(h + r)

This gives:

TSA = 2 * \frac{22}{7} * 7 * (15 + 7)

TSA = 2 * 22 * (15 + 7)

TSA = 2 * 22 * 22

TSA = 968cm^2

6 0
3 years ago
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