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Sveta_85 [38]
2 years ago
6

Classify the triangle by its sides. The lengths of the sides are 6, 8, and 8.

Mathematics
2 answers:
Anon25 [30]2 years ago
8 0
Isosceles
hope this helps
ziro4ka [17]2 years ago
6 0

Answer:

Isosceles

Step-by-step explanation:

An icosceles triangle has two sides with the same length.

6, 6, 8

6, 6, 8

<em>Isosceles</em>

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On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), c
77julia77 [94]

The graphed function, F(x), has a value greater than 0 over the intervals (-0.7, 0.76) and (0.76,  ∞) . F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞) is the correct statement [Fourth choice].

About a Graphed Function

The function graph of an object F stands for the set of all points in the plane that are (x, f(x)). The graph of f is also known as the graph of y = f. (x). The graph of an equation is thus a specific example of the graph of a function. A graphed function is a function that has been drawn out on a graph.

It is evident from the attached graph that the supplied function exceeds 0 for the following range:

-0.7 < F(x) < 0.76

And, 0.76 < F(x) < ∞

As a result, the intervals for which the given graphed function, F(x) is greater than 0 are as follows,

(-0.7, 0.76) and (0.76, ∞)

Learn more about a graphed function here:

brainly.com/question/27757761

#SPJ1

3 0
1 year ago
In triangle ABC, the length of side AB is 16 inches and the length of side BC is 23 inches. Which of the following could be the
Aleksandr [31]
A 31 inches is the answer because it can't be higher than 39

4 0
3 years ago
The A&amp;M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a
Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0
2 years ago
A town uses positive numbers to track increases in population and negative numbers to track decreases in population. The populat
Alex73 [517]
Well heres what to do


300 residents                         5yrs


divde 300 by 5= you get 60 a yr
5 0
3 years ago
Read 2 more answers
Solve the system of equations.<br><br> 5x + y = 9<br> 3x + 2y = 4
tiny-mole [99]
Y=-5x+9

3x+2(-5x+9)=4
3x-10x+18=4
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-7x=-14
x=2

5(2)+y=9
10+y=9
y=9-10
y=-1

The answer is (2,-1) :)
5 0
3 years ago
Read 2 more answers
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