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3 years ago

In simplest firm what is 5/8 + 3/10

Mathematics

2 answers:

Alecsey [184]3 years ago

7 0

37/40 would be the simplest form.

Dafna11 [192]3 years ago

4 0

Here's how you simplify this question

First you look at the denominators and see what both numbers go into.

In this case it would be 40

So you change the equation to 25/40 + 12/40

After that all you have to do is add

⊂ 37/40 ⊃

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5 The area of a rectangular lawn is 255 m². If its length is 15 m, find its perimeter.

Marina CMI [18]

Area of a rectangular lawn = l×b

255=15×x

Hence the breadth is 17 m

Hence perimeter =2(l+b)=2(15+17)=64

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3 years ago

Need help asap pls!!!

lisabon 2012 [21]

Answer:

Step-by-step explanation:

According to the given description, PS is the mid segment of the $\triangle TQR$

Therefore by Mid-segment Theorem:

$PS = \frac{1}{2} QR \\ \\ PS = \frac{1}{2} \times 32 \\ \\ PS =16 \:$

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2 years ago

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3 years ago

An arithmetic sequence with a third term of 8 and a constant difference of 5

Vanyuwa [196]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ \hrulefill\\[0.5em] a_3=8\\ n=3\\ d=5 \end{cases} \\\\\\ a_3=a_1+(3-1)5\implies 8=a_1+(2)5 \\\\\\ 8=a_1+10\implies -2=a_1 \\\\\\ \begin{cases} a_1=-2\\ d=5 \end{cases}\implies a_n=-2+(n-1)d$

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3 years ago

What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4

Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

$I = \frac{P}{4\pi d^{2}}$

<em>where P: is the power ans d: is the distance. </em>

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

$\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}$

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km </em>

$\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}$

$\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}$

$\frac{I_{1}}{I_{2}} = 5.9:1$

Therefore, the ratio of the intensities is roughly 6:1.

I hope it helps you!

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3 years ago