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Y_Kistochka [10]
3 years ago
15

EASY MATH PLEASE HELP! a^2 + a + a^2

Mathematics
2 answers:
Arada [10]3 years ago
6 0

a^2 evaluates to  

a^2+a evaluates to  

Multiply the exponent of a by 2giving

The answer is

a^2 evaluates to  

 + =

The answer is

a^2+a+a^2 evaluates to


Setler79 [48]3 years ago
5 0

Answer:

a^2+a+a^2 evaluates to

Step-by-step explanation:

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Two consecutive odd integers whose sum is 76.
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Answer:

37 and 39

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Find the value of x in the isosceles triangle shown below.
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Answer: C. 10

Explanation:

Take half right triangle from the isosceles triangle:

We get side lengths:

12/2 = 6, 8, and x

And use Pythagorean’s theorem to find x:

6^2 + 8^2 = x^2
36 + 64 = x^2
100 = x^2
10 = x
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Find the distance between (-1,4) and (-1,12)
lukranit [14]

Answer:

8 units

Step-by-step explanation:

Since both are on the same place in terms of the x-axis, this makes it much easier. Just go from (-1,4) and move upwards upon the graph until your at (-1,12). You counted 8 units. *mic drop*

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using the slope formula find the slope of the line through the points (0,0) and (3,9) use pencil and paper explain how you can u
maxonik [38]

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9/3

Step-by-step explanation:

you can't subtract from zero or you can't subtract a number from zero.

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3 years ago
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A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
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