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3 years ago

Find the nth term of a gp with (a. find term = 5, common ratio = 2

Mathematics

1 answer:

Rina8888 [55]3 years ago

7 0

Step-by-step explanation:

we know,

$tn= a {(r)}^{n - 1} \\ T5 = a {(2)}^{5 - 1} \\ t5 = a \times {2}^{4} \\ = 16a$

Therefore, nth term of a given gp is

16a

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Which expression represents "10 less than the product of 12 and 9"?

seraphim [82]

Answer:

answer.

Step-by-step explanation:

B. 12x9-10 is the answer

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3 years ago

What are the slope and y intercept of the line 4y= -x - 32

Alona [7]

First you'll have to bring the equation in form y = mx + b.

4y = -x - 32
y = -1/4 x - 8

So the slope is -1/4 and y-intercept is -8

Hope this helps :)

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3 years ago

Read 2 more answers

The number of students who chose lunch was 5 more than the number of students who chose breakfast. Write a system of linear equa

Papessa [141]

Answer:

The system of linear equations are $y=5+x$ and $x+y=25$

Step-by-step explanation:

Given : The number of students who chose lunch was 5 more than the number of students who chose breakfast. Let x represent the number of students who chose breakfast and y represent the number of students who chose lunch.

(50 students picked, 25 picked dinner the rest picked lunch and breakfast)

To find : Write a system of linear equations that represents the numbers of students who chose breakfast and lunch ?

Solution :

The number of students who chose breakfast be 'x'

The number of students who chose lunch be 'y'.

The number of students who chose lunch was 5 more than the number of students who chose breakfast.

i.e. $y=5+x$

Now, Total student were 50 and 25 picked dinner the rest picked lunch and breakfast i.e. 25.

So, $x+y=25$

Therefore, the system of linear equations are $y=5+x$ and $x+y=25$

4 0

3 years ago

Find all solutions of the equation: 2cos^2x-cosx=1

Art [367]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166243

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Solve the trigonometric equation:

$\mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}$

Make a substitution:

$\mathsf{cos\,x=t\qquad (-1\le t\le 1)}$

and the equation becomes

$\mathsf{2t^2-t-1=0}$

Rewrite conveniently – t as + t – 2t, and then factor the left-hand side by grouping:

$\mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}$

Factor out 2t + 1:

$\mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}$

Substitute back for t = cos x:

$\begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}$

Therefore,

$\begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}$

where k is an integer.

Solution set:

$\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}$

I hope this helps. =)

3 0

3 years ago

is it possible for a percent increase or decrease to be over 100% explain why or why not this is possible

Ivahew [28]

No because there has to be a remaining opposite persent

6 0

3 years ago

Find the nth term of a gp with (a. find term = 5, common ratio = 2​

Find the nth term of a gp with (a. find term = 5, common ratio = 2