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garri49 [273]
3 years ago
12

Find the nth term of a gp with (a. find term = 5, common ratio = 2​

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0

Step-by-step explanation:

we know,

tn= a {(r)}^{n - 1}  \\ T5 = a {(2)}^{5 - 1}  \\ t5 = a \times  {2}^{4}  \\  = 16a

Therefore, nth term of a given gp is

16a

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