X^2+9x-4=0 Solve by Quadratic formula. Please show all work

1 answer:

4 0

$x^{2} + 9x - 4 = 0$
$x = \frac{-9 +/- \sqrt{9^{2} - 4(1)(-4)}}{2(1)}$

$x = \frac{-9 +/- \sqrt{81 + 16}}{2}$

$x = \frac{-9 +/- \sqrt{97}}{2}$

$x = \frac{-9 +/- 9.848857802}{2}$

$x = \frac{-9 + 9.848857802}{2}$ <u /> $x = \frac{-9 - 9.848857802}{2}$

$x = \frac{0.848857802}{2}$ $x = \frac{-18.848857802}{2}$

$x = 0.424428901$ $x = -9.424428901$

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A square has sides of length 8.4 . Work out the length of a diagnol of the square . Give your answer correct to 3 significant fi

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Answer:

The length of the diagonal is 11.879 units

Step-by-step explanation:

On any rectangle or square, any 2 adjacent sides and the diagonal that connects them makes a right triangle. The diagonal is the hypotenuse of that right triangle, and you can find it using the pythagorean theorem:

$a^2+b^2=c^2$