Question

X^2+9x-4=0 Solve by Quadratic formula. Please show all work

Answer 1

$x^{2} + 9x - 4 = 0$
$x = \frac{-9 +/- \sqrt{9^{2} - 4(1)(-4)}}{2(1)}$

$x = \frac{-9 +/- \sqrt{81 + 16}}{2}$

$x = \frac{-9 +/- \sqrt{97}}{2}$

$x = \frac{-9 +/- 9.848857802}{2}$

$x = \frac{-9 + 9.848857802}{2}$    <u />$x = \frac{-9 - 9.848857802}{2}$

$x = \frac{0.848857802}{2}$    $x = \frac{-18.848857802}{2}$

$x = 0.424428901$    $x = -9.424428901$