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kiruha [24]
3 years ago
8

More help with math please. Thanks,

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
6 0
Triangles = 180 degrees. All you need to do is add up the other 2 and subtract it from 180 which will give you 118.
Elan Coil [88]3 years ago
5 0
Your Answer For X Is X=118
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What is the value of 6 in 3.651<br><br> A. Ones<br> B. Tenths<br> C. Tens<br> D. Hundredths
kobusy [5.1K]

Hey there!

<h2>Explanation</h2>

So the first digit of the decimal is called ones. After the decimal, it starts with tenths, then hundredths, and at last thousandths. But you see 6 in the tenths place so now you have your answer.

<h2>Answer</h2>

Your answer is B. Tenths

______________________________________________________

Hope this helps :)○_•

3 0
3 years ago
Read 2 more answers
1/5 greater or less than 2/6
Sonbull [250]
1/5=0.2. 2/6=0.3. 2/6 is greater. Or 1/5 is less than.
7 0
4 years ago
Use expressions for odd integers to confirm the conjecture that the product for two odd integers is an odd integer.
Mandarinka [93]

k, n - integers  

2k+1  - an odd integer

2n+1  - another odd integer

The product of them:

  (2k + 1)(2n + 1) =

= 4kn + 2k + 2n + 1 =

= 2(2kn + k + n) + 1

The product of integers (2kn) is integer

and the sum of them (2kn+k+n) also is integer

So  (2k + 1)(2n + 1)  = 2(2kn + k + n) + 1  is an odd integer

4 0
4 years ago
Find the nth term of the sequence 7,25,51,85,127​
olya-2409 [2.1K]

Let <em>a </em>(<em>n</em>) denote the <em>n</em>-th term of the given sequence.

Check the forward differences, and denote the <em>n</em>-th difference by <em>b </em>(<em>n</em>). That is,

<em>b </em>(<em>n</em>) = <em>a </em>(<em>n</em> + 1) - <em>a </em>(<em>n</em>)

These so-called first differences are

<em>b</em> (1) = <em>a</em> (2) - <em>a</em> (1) = 25 - 7 = 18

<em>b</em> (2) = <em>a</em> (3) - <em>a</em> (2) = 51 - 25 = 26

<em>b </em>(3) = <em>a</em> (4) - <em>a</em> (3) = 85 - 51 = 34

<em>b</em> (4) = <em>a </em>(5) - <em>a</em> (4) = 127 - 85 = 42

Now consider this sequence of differences,

18, 26, 34, 42, …

and notice that the difference between consecutive terms in this sequence <em>b</em> is 8:

26 - 18 = 8

34 - 26 = 8

42 - 34 = 8

and so on. This means <em>b</em> is an arithmetic sequence, and in particular follows the rule

<em>b</em> (<em>n</em>) = 18 + 8 (<em>n</em> - 1) = 8<em>n</em> + 10

for <em>n</em> ≥ 1.

So we have

<em>a </em>(<em>n</em> + 1) - <em>a </em>(<em>n</em>) = 8<em>n</em> + 10

or, replacing <em>n</em> + 1 with <em>n</em>,

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 8 (<em>n</em> - 1) + 10

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 8<em>n</em> + 2

We can solve for <em>a</em> (<em>n</em>) by iteratively substituting:

<em>a</em> (<em>n</em>) = [<em>a</em> (<em>n</em> - 2) + 8 (<em>n</em> - 1) + 2] + 8<em>n</em> + 2

<em>a</em> (<em>n</em>) = <em>a </em>(<em>n</em> - 2) + 8 (<em>n</em> + (<em>n</em> - 1)) + 2×2

<em>a</em> (<em>n</em>) = [<em>a</em> (<em>n</em> - 3) + 8 (<em>n</em> - 2) + 2] + 8 (<em>n</em> + (<em>n</em> - 1)) + 2×2

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 3) + 8 (<em>n</em> + (<em>n</em> - 1) + (<em>n</em> - 2)) + 3×2

and so on. The pattern should be clear; we end up with

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 8 (<em>n</em> + (<em>n</em> - 1) + … + 3 + 2) + (<em>n</em> - 1)×2

The middle group is the sum,

\displaystyle 8\sum_{k=2}^nk=8\sum_{k=1}^nk-8=\frac{8n(n+1)}2-8=4n^2+4n-8

so that

<em>a</em> (<em>n</em>) = <em>a</em> (1) + (4<em>n</em> ² + 4<em>n</em> - 8) + 2 (<em>n</em> - 1)

<em>a</em> (<em>n</em>) = 4<em>n</em> ² + 6<em>n</em> - 3

4 0
3 years ago
Write the equation of the line that it is parallel to 2x = 1 - 3y and passes through<br> (9,4).
Nezavi [6.7K]

Answer:

all work is shown and pictured

4 0
3 years ago
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