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3 years ago

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What is the value of 6 in 3.651 A. Ones B. Tenths C. Tens D. Hundredths

2 answers:

patriot [66]3 years ago

7 0

I believe the answer would be B!

kobusy [5.1K]3 years ago

3 0

Hey there!

<h2>Explanation</h2>

So the first digit of the decimal is called ones. After the decimal, it starts with tenths, then hundredths, and at last thousandths. But you see 6 in the tenths place so now you have your answer.

<h2>Answer</h2>

Your answer is B. Tenths

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Hope this helps :)○_•

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If you add the lengths of the focal radii of an ellipse, what other value will you produce?

ss7ja [257]

Equation of an ellipse

→having center (0,0) , vertex ( $(\pm a ,0)$ and covertex $(\pm b ,0)$ and focus $(\pm c ,0)$ is given by:

$\frac{x^2}{a^2} + \frac{y^2}{b^2}=1$

As definition of an ellipse is that locus of all the points in a plane such that it's distance from two fixed points called focii remains constant.

Consider two points (a,0) and (-a,0) on Horizontal axis of an ellipse:

Distance from (a,0) to (c,0) is = a-c = $F_{1}$

Distance from (-a,0) to (c,0) is = a + c = $F_{2}$

$F_{1} + F_{2} =$ a -c + a +c

= a + a

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8 0

3 years ago

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6. Evaluate the following expression: 10 + 4(6-2)<br> А. 56<br> B. 82<br> С. 18<br> D. 26

irakobra [83]

Answer:

D. 26

Step-by-step explanation:

$10+4(6-2)\\10+4(4)\\10+16\\26$

7 0

2 years ago

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Find the coordinates of the midpoint M of ST???????. Then find the distance between points S and T. Round the distance to the ne

Law Incorporation [45]

(7, 5)
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3 years ago

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2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

John finds a toy train set John finds a toy train set on sale for 20% off at a toy store. The original price was $35. John

Helen [10]

Well here's your answer straight <u><em>he must pay 29.82$ </em></u>and here's my work,

20% of 35 is 7 and since its 20% off we must subtract 35-7=28
Next it said there's a 6.5 tax so that means we are adding on to 28$
6.5 of 28 is 1.82 so we add 28+1.82 which equals your answer 29.82

5 0

3 years ago