Ask question

Ask question

All categories

melamori03 [73]

1 year ago

14

Name all sets of numbers to which each number belongs 1) -15 2) 11 3) square root of 30 4) 17/3 5) 6 6) 0 7) -13 8) 3 9) 10/11 1

0) 14 11) -13 12) 475/325 13) square root of 77 14) 6/7 15) square root of 0 16) negative square root of 196 17) -1 18) -16/-2 19) 135/-3

1 answer:

nikdorinn [45]1 year ago

3 0

The numbers belongs to the following number sets

1. -15 belongs to integers

2. 11 belongs to prime

3. rational number

4. rational number

5. composite number

6. whole number

7. Integers

8. whole numbers

9. rational numbers

10. whole numbers

11. Integers

12. rational number

13. rational number

14. rational number

15. whole number

16. integer

17. integer

18. whole number

19. integer

What are Number sets?

Number sets can be defined as group of numbers that have definite structural properties.

The sets of numbers given above has various properties which enabled its identification. Number sets can be integers, whole numbers, real numbers, complex numbers and many more.

In conclusion, the properties of each numbers enables us to identify its set.

Learn more about Number Sets: brainly.com/question/1871587

#SPJ4

You might be interested in

the table shows the price of sneakers in a store.40,37,25,35,29,43,34,26,39,43,51,47,35,27,45,28,50,41 . hat is the midian price

Yuliya22 [10]

Answer:

Median= 38

Step-by-step explanation:

First, put the order of numbers in least to greatest.

Next, Find the number(s) that are in the middle and add them together.

Then, divide them by 2 which gives you the answer of 38.

4 0

3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

Solve the system of equations. y = x2 + 7x - 5 y = 2x + 9

marissa [1.9K]

Answer:

(2, 13)

(-7, -5)

Step-by-step explanation:

Easiest and fastest way to do this is to graph the systems of equations and analyze the graph where the 2 graphs intersects.

6 0

3 years ago

Read 2 more answers

Find the area of the shaded region .

Greeley [361]

Calculate area of the white region inside circle.

Area of the two white triangles in top left and bottom right:

$2 \cdot \frac{1}{2}(6)(6) = 36 ft^2$

Area of the two white quarter circles in the bottom left and top right:

$2 \cdot \frac{1}{4}\pi (6)^2 = 18\pi ft^2$

Total area of unshaded white region inside circle:

$(36 + 18\pi)ft^2$

Area of entire circle including the white and shaded regions

$\pi(6)^2 = 36\pi ft^2$

Area of shaded region is area of entire circle - area of unshaded white region

$36\pi - (36 + 18\pi) = (18\pi - 36) ft^2$

7 0

2 years ago

Using the measurements of the shapes.. determine the area and perimeter of the irregular polygon.

Phoenix [80]

Answer:

43.8 is the Area but i don't know about the perimeter

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers