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ddd [48]
3 years ago
13

WHAT IS THE SOLUTION TO THIS EQUATION 1. 8x - 5(x- 3)= 18

Mathematics
2 answers:
marysya [2.9K]3 years ago
5 0

Answer:

x = 1

Step-by-step explanation:

8x - 5(x - 3) = 18

8x - 5x + 15 = 18   <em>[Expand the brackets]</em>

3x = 3   <em>[Separate variables and constants]</em>

<u>x = 1</u>

Leviafan [203]3 years ago
4 0
I got x=1 , you first use disputive property then simplify

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Colt1911 [192]

Answer:

line of best fit: y = -2.9114x + 46.569

Step-by-step explanation:

Plugging in your table into Excel, it turns out that y = -2.9114x + 46.569  provides a better fit of the data points into the line.  Please see the attached image for details.

Hope this helps.

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2 years ago
Rectangle A has length 12 and width 8. Rectangle B has length 15 and width 10. Rectangle C has length 30 and width 15.
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Answer:

Step-by-step explanation:

The length is x2 while the width is x1.5

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2 years ago
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3 years ago
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State the domain of the following : a. y = √ x + 1 /√ 25 − x^2 <br>b. f(x) = (√ 1 − x ) ln x
almond37 [142]

Answer:

a.) -1 < x < 5

b.) x <= 1

Step-by-step explanation: Domain is the independent variable (x).

For both question a and b, make sure that the number under the square root does not end up being negative. And the denominator of the fractional number is not equal to zero when variable x is being substituted for any value.

a.) y = √ x + 1 /√ 25 − x^2 

Domain : -1 < x < 5

That is the minimum value for x is 0 and the maximum value is 4

b. f(x) = (√ 1 − x ) ln x

Domain : x <= 1

That is, x is less than or equal to 1

The maximum value for x is 1. x can be

1, 0, -1, -2, -3, ..........

8 0
3 years ago
Find the terminal point on the unit circle determined by pi radians.
svet-max [94.6K]

Answer:

Terminal points

(x,y) = (\frac{1}{\sqrt{2} }) , (\frac{-1}{\sqrt{2} })

Step-by-step explanation:

According to the question, it is provided that

\theta = \frac{7\pi}{4}

Now

x = 1. cos (\frac{7\pi}{4})\\\\ = cos (2\pi - \frac{\pi}{4})\\\\= cos \frac{\pi}{4} \\\\= \frac{1}{\sqrt{2} }

y = 1. sin (\frac{7\pi}{4})\\\\ = sin (2\pi - \frac{\pi}{4})\\\\= -sin \frac{\pi}{4} \\\\= \frac{-1}{\sqrt{2} }

Now

(x,y) = (\frac{1}{\sqrt{2} }) , (\frac{-1}{\sqrt{2} })

These two represents the terminal points

We simply applied the above equations and then equate these two equations to determine the terminal points and therefore the same is to be considered

It could be figure out by using the x and y points

Therefore the two shows the terminal points

3 0
3 years ago
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