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3 years ago

WHAT IS THE SOLUTION TO THIS EQUATION 1. 8x - 5(x- 3)= 18

Mathematics

2 answers:

marysya [2.9K]3 years ago

5 0

Answer:

x = 1

Step-by-step explanation:

8x - 5(x - 3) = 18

8x - 5x + 15 = 18 [Expand the brackets]

3x = 3 [Separate variables and constants]

x = 1

Leviafan [203]3 years ago

4 0

I got x=1 , you first use disputive property then simplify

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4√6 •√3 how do I show work for this because the answer is 2√12

Yuliya22 [10]

Answer:

$4 \sqrt{6} \times \sqrt{3} = 12 \sqrt{2}$

Step-by-step explanation:

We want to simplify the radical expression:

$4 \sqrt{6} \times \sqrt{3}$

We write √6 as √(2*3).

This implies that:

$4 \sqrt{6} \times \sqrt{3} = 4 \sqrt{2 \times 3} \times \sqrt{3}$

We now split the radical for √(2*3) to get:

$4 \sqrt{6} \times \sqrt{3} = 4 \sqrt{2} \times \sqrt{3} \times \sqrt{3}$

We obtain a perfect square at the far right.

$4 \sqrt{6} \times \sqrt{3} = 4 \sqrt{2} \times (\sqrt{3} )^{2}$

This simplifies to

$4 \sqrt{6} \times \sqrt{3} = 4 \sqrt{2} \times 3$

This gives us:

$4 \sqrt{6} \times \sqrt{3} = 4 \times 3 \sqrt{2}$

and finally, we have:

$4 \sqrt{6} \times \sqrt{3} = 12 \sqrt{2}$

5 0

3 years ago

Polygon CCC has an area of 404040 square units. K 2ennan drew a scaled version of Polygon CCC using a scale factor of \dfrac12 1

nikdorinn [45]

Answer:

Area of polygon D = 10 square units

Step-by-step explanation:

Given:

Polygon C has an area of 40 square units.

It is scaled with a scale factor of $\frac{1}2$ to form a new polygon D.

To find:

The area of polygon D = ?

Solution:

When any polygon is scaled to half, then all the sides of new polygon are half of the original polygon.

And the area becomes one-fourth of the original polygon.

Let us consider this by taking examples:

First of all, let us consider a right angled triangle with sides 6, 8 and 10 units.

Area of a right angled triangle is given by:

$A = \dfrac{1}{2} \times Base \times Height\\\Rightarrow A = \dfrac{1}{2} \times 6 \times 8 = 24\ sq\ units$

If scaled with a factor $\frac{1}{2}$ , the sides will be 3, 4 and 5.

New area, A':

$A' =\dfrac{1}{2} \times 3 \times 4 = 6\ sq\ units = \dfrac{1}4\times A$

i.e. Area becomes one fourth.

Let us consider a rectangle now.

Sides be 8 and 10 units.

Area of a rectangle, A = $Length \times Width$ = 8 $\times$ 10 = 80 sq units.

Now after scaling, the sides will be 4 and 5 units.

New Area, A' = 4 $\times$ 5 =20 sq units

So, $\bold{A' = \frac{1}4 \times A}$

Now, we can apply the same in the given question.

$\therefore$ Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ Area of polygon C

Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ 40 = 10 sq units

4 0

2 years ago

Please help ..........................

Alenkinab [10]

Answer:

9/2

Step-by-step explanation:

perpendicular lines have slopes that are opposite and reciprocal

the reciprocal of -2/9 is 9/2

7 0

2 years ago

Question 2: If I increase the price of a dress by 15%, what would the multiplier be ?

sukhopar [10]

If the price was $1 and it increased by 15% it would now be $1.15 therefore the multiplier is 1.15 as that increases a number by 15%

6 0

3 years ago

draw a new location of the pole barn on the graph below. Note that the stock tank is located at the origin.

krok68 [10]

Answer:

i think you reflect across the axis

Step-by-step explanation:

i learned this

: )

6 0

3 years ago