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3 years ago

What is the value of /E/ +/F/, A.-9 B.-11 C.11 D.9?

Mathematics

1 answer:

Furkat [3]3 years ago

7 0

Answer:

Step-by-step explanation:

|E| + |F|

|1| + |-10|=11

Answer=11

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In Ryan Corporation, the first shift produced 5 1/2 times as many lightbulbs as the second shift. If the total lightbulbs produc

Andru [333]

Answer:

13750

Step-by-step explanation:

Let 'x' be the number of bulbs produced in second shift

Number of bulbs produced in 1st shift= 5.5x

Total number of bulbs= 5.5x+x

16250=5.5x+x

x=2500

Number of bulbs produced in shift 1= 5.5×2500

= 13750

7 0

2 years ago

Write the equation in standard form for the circle that has a diameter with endpoints (- 1, 12) and (- 1, 8)

matrenka [14]

Answer:

The equation in standard form is $(x + 1)^{2} + (y - 10)^{2} = 4$

Step-by-step explanation:

The distance from (-1, 12) to (-1, 8) = 4 = diameter of the circle. So, 2 = radius

The center of the circle is at (-1, 10)

The equation in standard form is $(x + 1)^{2} + (y - 10)^{2} = 4$

3 0

2 years ago

What is the value of X in the given triangle?

miskamm [114]

<h3>Answer: x = 65.4</h3>

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Work Shown:

cos(angle) = adjacent/hypotenuse

cos(x) = 5/12

x = arccos(5/12)

x = 65.375681647836 which is approximate

x = 65.4 after rounding to one decimal place

Make sure your calculator is in degree mode. The arccosine function is the same as the inverse cosine function (shortened to $\cos^{-1}$ ).

4 0

2 years ago

The path of a skateboarder can be modeled by the equation (x – 3)2 = –8(y – 8), where distance is in feet and air resistance is

yKpoI14uk [10]

The maximum height and horizontal distance is required.

Maximum height 8 feet; horizontal distance 16 feet

The given path is $(x-3)^2=-8(y-8)$

If the skateboarder jumps at x = 0 she will land at y = 0. However there will be at horizontal displacement.

$(x-3)^2=-8(0-8)\\\Rightarrow (x-3)^2=8^2\\\Rightarrow x-3=\pm 8\\\Rightarrow x-3=8\\\Rightarrow x=11$

$x-3=-8\\\Rightarrow x=-5$

The distance between -5 and 11 is $11-(-5)=16$

Middle point would be $\dfrac{16}{2}=8$ from $-5$ .

$-5+8=3$

So, $x=3$

The maximum height will be

$(3-3)^2=-8(y-8)\\\Rightarrow y-8=0\\\Rightarrow y=8$

The maximum height is 8 feet and the horizontal distance is 16 feet.

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6 0

2 years ago

Read 2 more answers

In 2decimal places 39.98015

Morgarella [4.7K]

Answer:

39.98

Explanation:

39.98015

0 < 5, so 2nd decimal stays at 8

6 0

1 year ago

Read 2 more answers