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Alex17521 [72]
3 years ago
13

I need this answer as soon as possible

Mathematics
1 answer:
enot [183]3 years ago
4 0

Answer:

1) 1       2) 1/729      3) 1/27                  4) -1/729

Step-by-step explanation:

plug them into calculator

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13 POINTS- please help me
allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures (6x+20)^{\circ} and (x+100)^{\circ} are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16

Then

(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}

17. Two parallel lines are cut by transversal. Angles with measures (2x+12)^{\circ} and (3x-22)^{\circ} are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34

Then

(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}

18. Two parallel lines are cut by transversal. Angles with measures (6x-7)^{\circ} and (5x+10)^{\circ} are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17

Then

(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}

19. The diagram shows two complementary angles with measures 2x^{\circ} and 56^{\circ}. The measures of complementary angles add up to 90^{\circ}, then

2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17

Hence,

2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}

Check:

34^{\circ}+56^{\circ}=90^{\circ}

20. Angles \angle 1 and \angle 2 are vertical angles. By vertical angles theorem, vertical angles are congruent, so

m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4

Hence,

m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}

21. \angle 5 and \angle 8 are supplementary. The measures of supplementary angles add up to 180^{\circ}, so

m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34

Therefore,

m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}

7 0
3 years ago
What is the value of 2c + d² - 3e + 4f when c = 3, d = 5, e = 6, and f = 1?
Andrej [43]

Answer:

17

Step-by-step explanation:

2c + d^3 - 3e +4f

=2(3) + (5^2) - 3(6) + 4(1)

=6+25-18+4

=17

5 0
3 years ago
Solve systems of equations by algebraically x-2y=7 <br> 2x+5y =5
Natali [406]

Answer:

(5,-1) or x=5 y=-1

Step-by-step explanation:

I used the substitution method to solve this!

<em>1. Pick one of your equations and solve for one of the variables. I chose the first equation and solved for x.</em>

x-2y=7

(Move the -2y to the other side of the equation in order to get the x by itself. You do the opposite, so it becomes +2y.)

x=2y+7

<em>2. Now take your second equation and plug in what you got for x into the x variable.</em>

2(2y+7)+5y=5

(Multiple 2 by everything inside of the parentheses.)

4y+14+5y=5

(We want to get the y by itself, so move the 14 to the other side.)

4y+5y=-14+5

(Combine all the like terms.)

9y=-9

(Divide the 9 from the y. What you do to one side you must do to the other.)

y=-1

<em>3. Since you have one variable solved for. Now take the first equation and plug in your y.</em>

x-2(-1)=7

(Multiple -2 by -1)

x+2=7

(Move the 2 to the other side in order to get the x by itself.)

x=5

<em>4. If needed, plug in your x and y values into the equations in order to check your answer.</em>

Hope this could help!

8 0
3 years ago
Read 2 more answers
Find the product of (3x-4)(2x^2+2x-1)
lapo4ka [179]

Answer:

6x^3  - 2x^2  -11x +4

Step-by-step explanation:

(3x-4)(2x^2+2x-1)

Multiply 3x  by the second term

3x* (2x^2+2x-1)

 6x^3  +6x^2 -3x


Multiply -4  by the second term

-4*(2x^2+2x-1)

 -8x^2 -8x+4


Add these together,  lining up the terms

 6x^3  +6x^2 -3x  

            -8x^2 -8x+4

----------------------------------

6x^3  - 2x^2  -11x +4

8 0
3 years ago
Read 2 more answers
Goran made 6 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 6 necklaces
Tema [17]
    6b + 6p = 33.60              ; b=2.90

6(2.90) + 6p = 33.60

17.40 + 6p = 33.60
-17.40           -17.40

    6p = 16.20
     /6         /6

      p = 2.70

ANSWER: each pendant costs $2.70
5 0
3 years ago
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