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swat32
4 years ago
12

Simplify the expression -2(p+4)^2-3+5p what is the simplified expression in standard form?

Mathematics
1 answer:
kolbaska11 [484]4 years ago
6 0

Answer

I got p-19 i might be wrong

Step-by-step explanation:

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Can someone help me with letter b along with an explanation.
lana66690 [7]

Step-by-step explanation:

Forced vital capacity: the maximum amount of air you can forcibly exhale from your lungs after fully inhaling. It is about 80 percent of total capacity, or 4.8 liters, because some air remains in your lungs after you exhale

7 0
3 years ago
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Which are the following statements is 6×7 = 42
Alex787 [66]

Answer:

A and B are both correct

Step-by-step explanation:

the definitions of the following words are:

factor- a number or quantity that when multiplied with another produces a given number or expression.

multiple- a number that can be divided by another number without a remainder.

6 multiplied with 7 equals 42

42 divided by 7 equals 6

another way of phrasing it:

7 and 6 are factors of 42

and

42 is a multiple of both 7 and 6

hope this helped!

8 0
3 years ago
Daniel has 6 teaspoons of salt. The ratio of teaspoons to tablespoons is 3 :1. How many tablespoons of salt does Daniel have
ddd [48]

Answer:

2

Step-by-step explanation:

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8 0
3 years ago
A sphere of radius r is cut by a plane h units above the equator, where
Anika [276]
Consider the top half of a sphere centered at the origin with radius r, which can be described by the equation

z=\sqrt{r^2-x^2-y^2}

and consider a plane

z=h

with 0. Call the region between the two surfaces R. The volume of R is given by the triple integral

\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx

Converting to polar coordinates will help make this computation easier. Set

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

Now, the volume can be computed with the integral

\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta

You should get

\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)
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