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docker41 [41]
4 years ago
8

The difference in the x-coordinates of two points is 3, and the difference in the y-coordinates of the two points is 6. What is

the slope of the line that passes through the points?
2
3
6
9
Mathematics
2 answers:
Makovka662 [10]4 years ago
5 0
To find the slope, use the rise/run technique with rise as the difference in y-coordinates and run as the difference in x-coordinates.  So, the rise is 6 units and the run is 3 units in this situation.  Now simply put it as a fraction: 6/3, which can be simplified to 2/1, or 2.
Digiron [165]4 years ago
4 0

Answer:

The answer is 2 happy solving GL.

Step-by-step explanation:

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Answer:

42

Step-by-step explanation:

Because of its shape I would imagine another flipped so it makes a square then solve for the square the divide.

7 x 12 =84

84÷2=42

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Prove, Cosec2A + cot2A = cotA​
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Proved

Step-by-step explanation:

Cosec2A + cot2A = cotA​

On Left hand-side

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4 years ago
What is the value of the expression 40.08÷1.2​
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33.4

Step-by-step explanation:

5 0
3 years ago
What is the value of cos theta in the diagram?
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3 0
4 years ago
Read 2 more answers
The quadratic mean of two real numbers x and y equals p (x 2 y 2)/2. By computing the arithmetic and quadratic means of differen
BARSIC [14]

Answer:

The quadratic mean of 2 real positive numbers is greater than or equal to the arithmetic mean.

Step-by-step explanation:

x and y      Quadratic Mean       Arithmetic mean

3 and 3                    3                                    3

2 and 3                   2.55                               2.5

3 and  6                  4.74                                4.5

2 and 5                   3.8                                  3.5

2 and 17                 12.1                                   9.5

18 and 28              23.5                                  23

10 and  48             34.7                                  29

The quadratic mean is always greater than the arithmetic mean except when  x and y are the same.

When the difference between the pairs is  small the difference in the means is also small. As that difference increases the difference in the means also increases.

So we conjecture that the quadratic mean is always greater than or equal to the arithmetic mean.

Proof.

Suppose it is true then:

√(x^2 + y^2) / 2) ≥ (x + y)/2       Squaring  both sides:

(x ^2 + y^2) / 2 ≥ (x + y)^2 / 4    Multiply through by 4:

2x^2 +2y^2  ≥  (x + y)^2

2x^2 +2y^2 >=  x^2 + 2xy + y^2

x^2 + y^2 >= 2xy.

x^2 - 2xy + y^2 ≥ 0

(x - y)^2 ≥ 0

This is true  because the square of any real number is positive so the original inequality must also be true.

6 0
3 years ago
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