Question

1.) Solve 2x^2-12x+20=0 using the quadratic solution set? What is the solution set?

Answer 1

Please, share just ONE problem at a time.  Thanks.

Solve 2x^2-12x+20=0:
Simplify this by dividing each term by 2:  x^2 - 6x + 10 = 0

Identify a, b and c:  a=1, b=-6 and c=10.  Then b^2=36.

Write out the solutions using the quadratic formula:

        6 plus or minus sqrt(36-40)
x = ---------------------------------------
                            2

sqrt(36-40) = sqrt(-4) = plus or minus i2

Then:
 
         6 plus or minus i2
x = --------------------------- (answer)
                  2