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2 years ago

Find the product of:

Mathematics

2 answers:

eduard2 years ago

5 0

Answer:

144/5

Step-by-step explanation:

$\large \rm \: 9 \frac{2}{3} \times 1 \frac{1}{29} \times \frac{6}{15 } \times 7 \frac{1}{5} \\ = \frac{29}{3} \times \frac{30}{29} \times \frac{6}{15} \times \frac{36}{5} \\ = 10 \times \frac{216}{75} \\ = \frac{2160}{75} \\ = \frac{144}{5}$

user100 [1]2 years ago

5 0

Answer:

9⅔ × 1¹/²⁹ × 6/15 × 7⅕ = 29/3 × 30/29 × 6/15 × 36/5 =(29/3 × 30/29) × (6/15 × 36/5) = (29×30 / 3×29) × (6×36 / 15×5) = (30/3) × (72/25) = 30×72 / 3×25 = 144 /5.

Please mark as brainliest answer.

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$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

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Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

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And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume an estimated proportion of $\hat p =0.5$ since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

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