The correct answer is A I believe
There are linear relationships so long as the power of x is 1 when power of y is 1 / power of x is not 2 and above when power of y is 1. This is assuming you plot the vertical axis as y-axis and the horizontal axis as the x-axis.
So using this concept, the equation with linear relationships are:
1, 3, 4, and 5.
Hope this helps! :)
Hello!
Since y is equal to both of them they are equal to each other
3x + 7 = 3x + 2
Now you solve it algebraically
Subtract 2 from both sides
3x + 5 = 3x
Subtract 3x from both sides
5 = 0
Since 5 does not equal 0 there are no solutions
The answer is D
Hope this helps!
Answer:
Step-by-step explanation:
Step 1: Subtract 10 from both sides.
2x2+20x−10=10−10
2x2+20x−10=0
For this equation: a=2, b=20, c=-10
2x2+20x+−10=0
Step 2: Use quadratic formula with a=2, b=20, c=-10.
x=
−b±√b2−4ac
2a
x=
−(20)±√(20)2−4(2)(−10)
2(2)
x=
−(20)±√(20)2−4(2)(−10)
2(2)
x=
−20±√480
4
x=−5+√30 or x=−5−√30
Answer:
x=−5+√30 or x=−5−√30
Answer:
1. 90
2.60
3.30
4. 40
5. 80
6. 60
7. 30
8. 30
9. 120
Total for all triangles=180
Step-by-step explanation:
In all the problems, you have to solve for y. This can be done because the three angles are supplementary For example, in the first diagram, you have:
3y+2y+y=180
6y=180
y=30
It's fairly easy to solve from there. Just more multiplying and subtracting.