<em><u>GIVEN</u></em><em><u> </u></em><em><u>EQUATION</u></em><em><u> </u></em><em>:</em><em>-</em>
<em>x</em><em> </em><em>+</em><em> </em><em>6</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>9</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em><u> </u></em><em><u> </u></em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>•</em><em>•</em><em>•</em><em> </em><em>(</em><em>i</em><em>)</em>
We have to find missing coordinate in ordered pair (2,?).
From ordered pair , we can observe that value of x is 2.
Putting value of x in equation (i).
2 + 6 y = 9
=> 6y = 9 -2
=> 6y = 7
=> y = 6/7
=> y = 0.8571428571
=> y = 0.86 (approx )
Now , ordered pair is ( 2, 0.86)
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Answer:
a/(a-6) = ab + 4.
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
180 ÷ 15 = 12
15 can go into 180 , 12 times
15 x 12 = 180
Answer: Hello there!
this type of equations in one dimension (when all the factors are constants) are written as:
h = initial position + initial velocity*t + (acceleration/2)*t^2
First, let's describe the hunter's equation:
We know that Graham moves with a velocity of 1.5 ft/s, and when he is 18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.
If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:
h = 18 + 1.5t
where t in seconds.
Now, the equation for the ball:
We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)
the equation for the ball is:
h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2
So the system is:
h = 18 + 1.5t
h = 5 +24t - 16.1t^2
so the right answer is A