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Y_Kistochka [10]
2 years ago
9

The jeweler buys gold for 1235.55 per ounce and resells it for 1376.44 per ounce how much profit does the jeweler make from buyi

ng and reselling ounces of gold
Mathematics
1 answer:
AnnZ [28]2 years ago
4 0

Profit made by jeweler from buying and reselling ounces of gold is 140.89 per ounce

<u>Solution:</u>

Given that

Price at which jeweler buy gold = 1235.55 per ounce

Price at which jeweler resells gold = 1376.44 per ounce

We need to calculate profit.

Buying price of 1 ounce of gold = 1235.55

Reselling price of 1 ounce of gold = 1376.44  

<em>Profit = Reselling price – buying price</em>

So profit on 1 ounce of gold = 1376.44 – 1235.55 = 140.89  

Hence profit made by Buying and Selling gold will be 140.89 per ounce

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Population density (people per square mile) is found by dividing population by square miles. The appropriate numbers are found in choices A and B, but only choice B uses the <em>divided by</em> operation.

The appropriate choice is ...

... B) 1.2e6÷1.1e4

3 0
3 years ago
The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
Ryan has 1/2 pound of chocolate. He divides it into 4 equal portions. Write the amount of chocolate, in pounds, in each portion
Vladimir [108]

Answer:

1/8

Step-by-step explanation:

Ryan has 1/2 pound of chocolate

He divided into 4 portions

Therefore the amount each of them will get can be calculated as follows

1/2 ÷ 4

= 1/2 × 1/4

= 1/8

Hence each portion Is 1/8

7 0
3 years ago
12x &gt; 10(2x-3) -10
KATRIN_1 [288]

Answer:

no

Step-by-step explanation:

12x-20x=-8x

so it would be -8x>-40

and you would divide both sides by -8

and get x<5

7 0
2 years ago
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Please help i know it a lot but please
blsea [12.9K]

Answer:

I have no clue

Step-by-step explanation:

I'm in middle school I don't know

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2 years ago
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