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Tanzania [10]
3 years ago
15

Graph the line y=1/2x+3

Mathematics
2 answers:
AnnZ [28]3 years ago
8 0

Answer:

to find the line you must find x and y

Step-by-step explanation:

\left[\begin{array}{ccc}x&-6&0\\y&0&3\end{array}\right]

graph the line using slope and y intercept

slop:1/2

y-intercept:3

find the values of mx and b

m=\frac{1}{2}\\b=3

find x intercept

0=\frac{x}{2}+3

re wright the equasion

\frac{x}{2}+3=0

subtract 3

\frac{x}{2} +3-3=0-3

\frac{x}{2}=-3

multiply by 2

*2\frac{x}{2}=-3*2

x intercept = -6

now find y intercept

y=\frac{0}{2}+3

divide by 2

y=0+3

add 0 and 3

y=3

create a table of x and y \left[\begin{array}{ccc}x&-6&0\\y&0&3\end{array}\right]

graph the line using y-intercept and slope

so your answer is (-6,3)

DerKrebs [107]3 years ago
8 0

STANDARD FORM:

  • <u>Slope-intercept form</u> :— y = mx + b, where m is slope & b is y-intercept.

ANSWER:

  • <u>Given equation</u> :— y = 1/2x + 3

This is slope intercept form of a line where slope of line is 1/2.

⇒y = 1/2x + 3, where slope is equal to 1/2 and y-intercept is 3.

NOTE: See picture attached.

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Clare made $160 babysitting last summer. She put the money in a savings account that pays 3% interest per year. If clare doesn't
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We have been given that Clare made $160 babysitting last summer. She put the money in a savings account that pays 3% interest per year. If Clare doesn't touch the money in her account, she can find the amount she'll have the next year by multiplying her current amount 1.03.

We are asked to write an expression for the amount of money Clare would have after 30 years if she never withdraws money from her account.

We will use exponential growth function to solve our given problem.

An exponential growth function is in form y=a(1+r)^x, where

y = Final value,

a = Initial value,

r = Growth rate in decimal form,

x = Time.

3\%=\frac{3}{100}=0.03

We can see that initial value is $160. Upon substituting our given values in above formula, we will get:

y=160(1+0.03)^x

y=160(1.03)^x

To find amount of money in Clare's account after 30 years, we need to substitute x=30 in our equation.

y=160(1.03)^{30}

Therefore, the expression 160(1.03)^{30} represents the amount of money that Clare would have after 30 years.

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Step-by-step explanation:

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FIRST CORRECT ANSWER GETS BRAINLIEST AND 50 POINTS.
AnnyKZ [126]

Answer:

A) 5^3*5^{-4}=5^{3-4}=5^{-1}=\frac{1}{5} (Yes. It has a value between zero and one.)

B) \frac{3^5}{3^{-6}}=3^{5-\left(-6\right)}=3^{5+6}=3^{11}=177147 (No. It does not have a value between zero and one.)

C) \left(\frac{1}{4}\right)^3* \left(\frac{1}{4}\right)^2=\left(\frac{1}{4}\right)^{3+2}=\left(\frac{1}{4}\right)^5=\frac{1^5}{4^5}=\frac{1}{1024}. (Yes. It has a value between zero and one.)

D) \frac{\left(-7\right)^5}{\left(-7\right)^7}=\left(-7\right)^{5-7}=\left(-7\right)^{-2}=\frac{1}{\left(-7\right)^2}=\frac{1}{49} (Yes. It has a value between zero and one.)

4 0
3 years ago
Read 2 more answers
Please help me with this question
Alex17521 [72]

Answer:

The answer is C.

Step-by-step explanation:

5*6=30

5 0
3 years ago
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