Find dy/dx using implicit differentiation cos x + sin y = 1

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

Differentiate both sides with respect to x, using the chain rule for the sine term:

$\cos(x) + \sin(y) = 1$

$\implies -\sin(x) + \cos(y)\dfrac{\mathrm dy}{\mathrm dx} = 0$

Solve for dy/dx :

$-\sin(x) + \cos(y)\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ \cos(y) \dfrac{\mathrm dy}{\mathrm dx} = \sin(x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\sin(x)}{\cos(y)}}$

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