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morpeh [17]
3 years ago
8

A wise man once said, “200 reduced by 3 times my age is 29.” What’s is his age?

Mathematics
2 answers:
Elenna [48]3 years ago
6 0

Answer:

57

Step-by-step explanation:

x=age

200-3x=29

x=57

ehidna [41]3 years ago
4 0

The man's age is 57 years old.

To find this answer follow the steps below:

1. Subtract 29 from 200 to get 171.

2. Divide 171 by 3 to get 57.

To check this, use the equation 200 - (57 x 3) = 29.

1. 57 x 3 = 171. 200 - 171 = 29

2. 200 - 171 = 29. 29 = 29.

Thus meaning the man is 57 years old. I hope this helps!

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Answer:

The area of the roof: ≈2287.44 ft^2, the lateral area of the roof:≈1580.58 ft^2

Step-by-step explanation:

The area of the roof is computed by the equation of the area of a cone:
A = πr(r + \sqrt{h^{2}+r^(2) })
(r: radius, h: height, πr^2 is the area of the base of the cone, πr\sqrt{h^{2}+r^(2) } is the lateral area of the cone). So:

A = 15\pi (15 + \sqrt{30^{2} +15^{2}  } ) ≈ 2287.44 ft^2.

As I stated earlier, the lateral area of the roof can be computed:

AL=15\pi \sqrt{30^{2} +15^{2} } ≈ 1580.58 ft^2.

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Answer:

A. No real solution

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C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

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So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
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