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yKpoI14uk [10]
2 years ago
6

Chemistry help. Will give Brainliest!

Chemistry
1 answer:
VashaNatasha [74]2 years ago
8 0
#1. An element or ion that has lost two electrons must have a net charge of 2+, because it has two more protons than electrons, therefore the answer is Mg2+

#2. aluminum ions have an oxidation state of 3+ and fluoride has an oxidation state of 1-, therefore I’m order for the charges to cancel you need 3 fluoride ions.
Therefore, the answer is AlF3
You might be interested in
What do a mole of magnesium and a mole of iron have in common
Vanyuwa [196]
The mole of anything has the same amount of particles and it is equal 
6.02* 10^{23}.

So a mole of magnesium and a mole of iron have the same number of atoms and it is equal
6.02*10²³
6 0
2 years ago
What changes would occur at a molecular level if a liquid is placed in cool conditions?
Dafna1 [17]

Answer: Option (C) is the correct answer.

Explanation:

Movement of particles in a substance is responsible for change in state of the substance or matter.

This means that more is the motion of particles more will be their kinetic energy.  

Also, kinetic energy is directly proportional to temperature.  

                     K.E = \frac{3}{2}kT  

So, less is the temperature of an object or substance less will be be the motion of its particles. Therefore, molecules will come closer to each other and state of substance will change from liquid to solid.

Thus, we can conclude that the motion of the molecules would decrease at a molecular level if a liquid is placed in cool conditions.

6 0
2 years ago
__________ ammonium compounds are less effective against gram-negative bacteria and more effective against gram-positive bacteri
Marina86 [1]

Answer:

Quartenary.

Explanation:

Quaternary ammonium compounds (QACs) are cationic salts of organically substituted ammonium compounds and have a broad range of activity against microorganisms, i.e more effective against Gram-positive bacterium at lower concentrations than Gram-negative bacteria.

It was also reported previously that monoalkyl QACs bind by ionic and hydrophobic interactions to microbial membrane surfaces, with the cationic head group facing outwards and the hydrophobic tails inserted into the lipid bilayer, causing the rearrangement of the membrane and the subsequent leakage of intracellular constituents.

6 0
2 years ago
Calculate Delta G for each reaction using Delta Gf values: answer kJ ...thank you
Leni [432]

Answer:

a) \Delta G=2.6kJ

b) \Delta G=-979.57kJ

c) \Delta G=264.21kJ

Explanation:

Hello,

In this case, in each reaction we must subtract the Gibbs free energy of formation the reactants to the Gibbs free energy of formation of the products considering each species stoichiometric coefficients. In such a way, the Gibbs free energy of formations are:

\Delta _fG_{H_2}=\Delta _fG_{I_2}=0kJ/mol\\\Delta _fG_{HI}=1.3kJ/mol\\\Delta _fG_{CO_2}=-394.4kJ/mol\\\Delta _fG_{CO}=-137.3 kJ/mol\\\Delta _fG_{NH_3}=16.7 kJ/mol\\\Delta _fG_{HCl}=-95.3kJ/mol\\\Delta _fG_{MnO_2}=465.37kJ/mol\\\Delta _fG_{Mn}=0kJ/mol\\\Delta _fG_{NH_4Cl}=-342.81kJ/mol

So we proceed as follows:

a)

\Delta G=2\Delta _fG_{HI}-\Delta _fG_{H_2}-\Delta _fG_{I_2}\\\\\Delta G=2*1.3\\\\\Delta G=2.6kJ

b)

\Delta G=\Delta _fG_{Mn}+2*\Delta _fG_{CO_2}-\Delta _fG_{MnO_2}-2*\Delta _fG_{CO}\\\\\Delta G=0+2*-394.4-465.37-2*-137.3\\\\\Delta G=-979.57kJ

c)

\Delta G=\Delta _fG_{NH_3}+\Delta _fG_{HCl}-\Delta _fG_{NH_4Cl}\\\\\Delta G=16.7-95.3-(-342.81)\\\\\Delta G=264.21kJ

Regards.

6 0
3 years ago
PLEASE HELP FAST !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
MakcuM [25]
The answer is D: 400N
your welcome

5 0
3 years ago
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