Answer:
<u>Number of electrons</u> = 118
<u>Electronic configuration</u>: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶
Explanation:
Given: A chemical element that has completely filled 7p orbital.
According to this, the principal occupied electron shell or the <u>valence shell of such an element is 7p.</u>
⇒ the principal quantum number <u>(n) for the valence shell is 7.</u>
∴ this element belongs to the period 7 of the periodic table.
Also, an element that has completely filled p-orbital belongs to the group 18 of the p-block.
Therefore, an element that belongs to the group 7 and period 18 of the periodic table, should have a <u>completely filled 5f, 6d, 7s and 7p orbitals</u>.
Therefore, the electronic configuration should be: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶
And, the <u>number of electrons</u> = atomic number of radon (Rn) + 14 + 10 + 2 + 6 = 86 + 32 = <u>118</u>.
<u>Therefore, the given element has atomic number 118 and has the electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶. Thus the given element can be Oganesson.</u>
