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daser333 [38]
3 years ago
13

3 by 3 cube is constructed of 27 blocks. How many blocks are needed to construct a cube with twice the dimensions of the origina

l cube?
Mathematics
1 answer:
Strike441 [17]3 years ago
5 0
"Twice the dimensions" means the length, width, and height
of the new cube are all 6.

To build that cube, you need (6 x 6 x 6) = 216 blocks.
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Answer:

The answer to your question is 20 feet

Step-by-step explanation:

Data

A = (-2, 1)

B = (4, 1)

C = (-2, -3)

D = (4, -3)

Process

1.- Calculate the distance from C and D

dCD = \sqrt{(4 + 2)^{2} + (3 - 3)^{2}}

dCD = \sqrt{6^{2}}

dCD = 6

2.- Calculate the distance from A to C

dAC = \sqrt{(2 - 2)^{2} + (-3 - 1)^{2}}

dAC = \sqrt{4^{2}}

dAC = 4

3.- Calculate the perimeter

Perimeter = 2(dCD) + 2(dAC)

-Substitution

Perimeter = 2(6) + 2(4)

-Simplification

Perimeter = 12 + 8

-Result

Perimeter = 20 ft

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