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4 years ago

How do you multiply integers

Mathematics

2 answers:

Bumek [7]4 years ago

8 0

5 times 4 equals 20. that's how

Ray Of Light [21]4 years ago

7 0

P x P = P

N x N = P

P x N = N

N x P = N

Negative - N

Positive - P

Multiply - x

Equal - =

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Select each problem that has a quotient of 2.5.

weqwewe [10]

Answer: 1 and 4

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4 years ago

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Use linear approximation to approximate 25.3‾‾‾‾√ as follows. Let f(x)=x√. The equation of the tangent line to f(x) at x=25 can

loris [4]

Answer:

Approximation f(25.3)=5.03 (real value=5.0299)

The approximation can be written as f(x)=0.1x+2.5

Step-by-step explanation:

We have to approximate $f(25.3)=\sqrt{25.3}$ with a linear function.

To approximate a function, we can use the Taylor series.

$f(x)=\sum_1^{\infty} \frac{f^{(n)}(a)}{n!}(x-a)^n$

The point a should be a point where the value of f(a) is known or easy to calculate.

In this case, the appropiate value for a is a=25.

Then we calculate the Taylor series with a number of terms needed to make a linear estimation.

$f(x)\approx f(a)+\frac{f'(a)}{1!}(x-a)$

The value of f'(a) needs the first derivate:

$f'(x)=\frac{1}{2\sqrt{x}}\\\\f'(a)=f'(25)=\frac{1}{2\sqrt{25}}=\frac{1}{2*5}=\frac{1}{10}$

Then

$f(x)\approx f(25)+\frac{1}{10}(x-25)=\sqrt{25} +\frac{1}{10}(x-25)\\\\f(x)\approx 5+\frac{1}{10}(x-25)$

We evaluate for x=25.3

$f(25.3)\approx 5+\frac{1}{10}(25.3-25)\\\\f(25.3)\approx 5+\frac{1}{10}(0.3)=5.03$

If we rearrange the approximation to be in the form mx+b we have:

$f(x)\approx 5+\frac{1}{10}(x-25)=5+0.1x-2.5\\\\f(x)\approx 0.1x+2.5$

Then, m=0.1 and b=2.5.

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4 years ago

Find the numbers a, b and c if the polynomial x3−18x2+24xb−c is the cube of the binomial x+2a.

mojhsa [17]

Answer:

$a=-3\\ \\b=\dfrac{9}{2}\\ \\c=216$

Step-by-step explanation:

Use formula

$(u+v)^3=u^3+3u^2v+3uv^2+v^3.$

Hence,

$(x+2a)^3=x^3+3x^2\cdot 2a+3x\cdot (2a)^2+(2a)^3=x^3+6ax^2+12a^2x+8a^3.$

This expression is equal to

$x^3-18x^2+24bx-c,$

so we can equate the coefficients at powers of x:

$x^3:\ 1=1\\ \\x^2:\ 6a=-18\Rightarrow a=-3\\ \\x:\ 12a^2=24b\Rightarrow b=\dfrac{9}{2}\\ \\1=x^0:\ 8a^3=-c\Rightarrow c=-8\cdot (-3)^3=216.$

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