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3 years ago

12

4x – 4 – 3x > 13 – 7x – 1 + 8

1 answer:

Rashid [163]3 years ago

4 0

If you would like to solve the inequation 4 * x - 4 - 3 * x > 13 - 7 * x - 1 + 8, you can do this using the following steps:

4 * x - 4 - 3 * x > 13 - 7 * x - 1 + 8
4 * x - 3 * x + 7 * x > 4 + 13 - 1 + 8
8 * x > 24 /8
x > 24/8
x > 3

The correct result would be x > 3.

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

Given : $\cos (180^{\circ}-q)=-\cos q$

We have to write which identity we will use to prove the given statement.

Consider $\cos (180^{\circ}-q)=-\cos q$

Take left hand side of given expression $\cos (180^{\circ}-q)$

We know

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Substitute , we get,

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Also, we know $\sin 180^{\circ}=0$ and $\cos 180^{\circ}=-1$

Substitute, we get,

$\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0$

Simplify , we get,

$\cos (180^{\circ}-q)=-\cos (q)$

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Step-by-step explanation:

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2 years ago