The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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The value of the trigonometry are sin(Π-Ɵ) = 0.84 and sin(Π + Ɵ) = -0.84
According to the question, there is a circle whose radius is 1 and the ray intersects the circle at point (0.54, 0.84).
We need to find the trigonometric values, that is
sin(Π-Ɵ) = sin(Ɵ) as we know that when the angle is in third quadrant sin is positive.
sin(Π+Ɵ) = -sin(Ɵ) as we know that when the angle is in fourth quadrant sin is negative.
Also note that, sinƟ = perpendicular/hypotenuse
Perpendicular = 0.84 as the perpendicular length will be equal to the length of the y-axis
Hypotenuse = 1 as the hypotenuse will be the radius of the circle which is formed by the ray.
Thus, sinƟ = 0.84/1 = 0.84
Hence, sin(Π-Ɵ) = 0.84
And sin(Π+Ɵ) = -0.84
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If u tell me the solution's like are u evaluating or what, which method is it i can tell u the answer <span />
Answer:
A cube
Step-by-step explanation:
If you fold it, you'll see
