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Tanzania [10]
3 years ago
13

A consumer charges a $46.92 purchase on a credit card. The card has a daily interest rate of 0.039%. If the consumer pays off th

e balance at the end of 30 days, how much in interest will be paid for the purchase?
a.
$0.06
b.
$0.18
c.
$0.55
d.
$5.49


The answer is C
Mathematics
2 answers:
masya89 [10]3 years ago
4 0

c I think its not D or A for sure


Nataliya [291]3 years ago
4 0
The answer is coming
Miltiply the amount by percent then your answer you multiply by 30 days
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yes

Step-by-step explanation:

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Standardized​ exam's scores are normally distributed. In a recent​ year, the mean test score was 21.2 and the standard deviation
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3 years ago
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
2 years ago
When Rs. 600 is divided between Ram and Shyam in the ratio 5:7 find how much money will get by Ram​
Neporo4naja [7]

Answer:

250 Rs.

Step-by-step explanation:

600 / 12 x 5 = 250 Rs.

Ram will get 250 Rs.

7 0
2 years ago
The radius r of a circle is increasing at a rate of 7 centimeters per minute. (a) find the rate of change of the area when r = 1
VikaD [51]
Dr /dt = 7

A = pi r^2

dA / dr = 2pir

dA/dt = dA/dr  * dr/dt = 2pir * 7  = 14pir

when r = 12   rate of change of the area =  14*pi*12  =  168pi

            =  527.79 cm^2 / minute to nearest hundredth
5 0
3 years ago
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