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3 years ago

Write down in terms of n, an expression for the nth term of the following sequences: 12,10,8,6,4

Mathematics

1 answer:

blagie [28]3 years ago

3 0

Answer:

The common difference is -2, so the formula for the nth term is 12-2(n-1).

This can be written 12-2n+2=14-2n, so that when n=1, the 1st term is 14-2=12.

The 5th term is 14-10=4; the 6th is 14-12=2. And so on

Step-by-step explanation:

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HELP with these two.

soldier1979 [14.2K]

Answer:

1. d = -6 2. n = -80

Step-by-step explanation:

If you divide 42 by -252 you get -6. And if you use your mental math you see that two negatives make a positive then you see it has to be negative and 80/4= 20 than -80/-4 = 20. Hope this helps, let me know if correct, and have a great day!!

4 0

3 years ago

Read 2 more answers

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago

What are multiples of 7

Brut [27]

Answer:

7 x 1 = 7

7 x 2 = 14

7 x 3 = 21

7 x 4 = 28

7 x 5 = 35

7 x 6 = 42

7 x 7 = 49

7 x 8 = 56

7 x 9 = 63

7 x 10 = 70

7 x 11 = 77

7 x 12 = 84

4 0

3 years ago

Read 2 more answers

The admission fee at an amusement park is $1.50 for children and $5.00 for adults. On a certain day, 344 people entered the park

marin [14]

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7 0

3 years ago

The workers' union at a particular university is quite strong. About 96% of all workers employed by the university belong to the

vredina [299]

Answer: 0.1699

Step-by-step explanation:

Given: The proportion of all workers employed by the university belong to the workers' union = 0.96

Sample size : n= 5

Binomial probability distribution formula :

$P(X=x)= \ ^nC_xp^x(1-p)^x$

The probability that exactly 4 of the workers interviewed are union members :-

$P(X=4)=^5C_4(0.96)^4(1-0.96)^1\\\\=(5)(0.96)^4(0.04)\\\\=(5)(0.84934656)(0.04)\\\\=0.169869312\approx0.1699$

Required probability = 0.1699

7 0

3 years ago