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qwelly [4]
3 years ago
7

The workers' union at a particular university is quite strong. About 96% of all workers employed by the university belong to the

workers' union. Recently, the workers went on strike, and now a local TV station plans to interview 5 workers (chosen at random) at the university to get their opinions on the strike. What is the probability that exactly 4 of the workers interviewed are union members
Mathematics
1 answer:
vredina [299]3 years ago
7 0

Answer: 0.1699

Step-by-step explanation:

Given: The proportion of all workers employed by the university belong to the workers' union = 0.96

Sample size : n= 5

Binomial probability distribution formula :

P(X=x)= \ ^nC_xp^x(1-p)^x

The probability that exactly 4 of the workers interviewed are union members :-

P(X=4)=^5C_4(0.96)^4(1-0.96)^1\\\\=(5)(0.96)^4(0.04)\\\\=(5)(0.84934656)(0.04)\\\\=0.169869312\approx0.1699

Required probability = 0.1699

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see explanation

Step-by-step explanation:

Given a quadratic equation in standard form, ax² + bx + c = 0 ( a ≠ 0 )

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