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galina1969 [7]
4 years ago
8

Please help I'm stuck on this :(

Mathematics
2 answers:
lidiya [134]4 years ago
8 0

Answer:

Step-by-step explanation:

y = -x + 2

2x - y = 7

I think you would benefit from graphing these equations yourself and then identifying the coordinates of their intersection.  To help you get started out:

Line 1:  Here the slope is -1 and the y-intercept is 2.  Plot a dark dot at (0, 2).  Now, starting with your pencil point on that dot, move 1 unit to the right and from this new location move 1 unit down.  Plot another dark dot there.  Now draw a line through these two dots.

Line 2:  2x - y = 7 when solved for y is   y = 2x - 7, which has a slope of 2 and y-intercept of -7.  Plot a dot at (0, -7).  From that point, move 1 unit to the right and from this new location move 7 units down.  Plot another dot there.  Draw a line thru these two dots.

Identify the coordinates of the point of intersection of these two lines.  For your reference I will find the solution using elimination by addition and subtraction.  Rewrite 2x - y = 7 as y = 2x - 7:

y = 2x - 7

y = -x   +2

--------------     SUBTRACT the second equation from the first, obtaining:

0  = 3x - 9.  Then 3x = 9 and x = 3.  Subbing 3 for x in y = 2x - 7, we get y = 2(3) - 7, or y = -1.

The two lines intersect at the point (3, -1).

Bezzdna [24]4 years ago
7 0

Answer:

See the picture below for the graph.

To solve the given system of equations, we have to find the intersecting point of the two lines.

As shown in the picture below, the intersecting point is (3, -1).

Therefore, x = 3 and y = -1.

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The population of a city is modeled by P(t)=0.5t2 - 9.65t + 100,where P(t) is the population in thousands and t=0 corresponds to
ira [324]

Answer:

Step-by-step explanation:

This equation is a positive parabola, opening upwards.  Parabolas of this type have a vertex that is a minimum value.  In order to find the year where the population was the lowest, we have to complete the square to find the vertex.  The rule for completing the square is to first set the parabola equal to 0, then next move the constant over to the other side of the equals sign.  The leading coefficient on the x-squared term HAS to be a positive 1.  Ours is a .5, so will factor it out.  Doing those few steps looks like this:

.5(t^2-19.3t)=-100

Next we take half the linear term, square it, and add it to both sides.  Don't forget the .5 sitting out front there as a multiplier.  Our linear term is 19.3.  Taking half of that gives us 9.65, and 9.65 squared is 93.1225

.5(t^2-19.3t+93.1225)=-100+46.56125

In this process, we have created a perfect square binomial on the left.  Stating that binomial and doing the addition on the right looks like this:

.5(t-9.65)^2=-106.8775

Now finally we will divide both sides by .5 then move over the constant again to get the final vertex form of this quadratic:

(t-9.65)^2+106.8775=y

From this we can see that the vertex is (9.65, 106.8775) which translates to the year 2009 and 107,000 approximately.

In our situation, that means that the population was at its lowest, 107,000 in the year 2009.

For part b. we will replace the y in the original quadratic with a 200,000 and then factor to find the t values.  Setting the quadratic equal to 0 allows us to factor to find t:

0=.5t^2-9.65t-199900

If you plug this into the quadratic formula you will get t values of

642.02 and -622.72

The two things in math that will never EVER be negative are distances/measurements and time, so we can safely disregard the negative value of t.  Since the year 2000 is our t = 0 value, then we will add 642 years to the year 2000 to get that

In the year 2642, the population in this town will reach 200,000 (as long as it grows according to the model).

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