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zubka84 [21]
2 years ago
10

What is the distributive property of 6(14+7)

Mathematics
1 answer:
IgorC [24]2 years ago
7 0

Answer:

126

Step-by-step explanation:

6 (14 + 7)

6 (21)

126

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Student Debt – Vermont: The average student loan debt of a U.S. college student at the end of 4 years of college is estimated to
mezya [45]

Answer:

The confidence interval is (24116.3878,24883.6122).

Step-by-step explanation:

We are given the following information in the question:

Population mean, \mu = $23,500

Sample mean,\bar{x} = $24,500

Sample standard deviation,s = $2,800

Sample size, n =  146

Confidence interval:

\bar{x} \pm t_{critical}\frac{s}{\sqrt{n}}  

Putting the values, we get,

t_{critical}\text{ at}~\alpha_{0.05} = \pm 1.655436

24500 \pm 1.65543(\frac{2800}{\sqrt{146}} ) = 24500 \pm 383.6122 = (24116.3878,24883.6122)

The confidence interval is (24116.3878,24883.6122).

5 0
2 years ago
Please help me with this one!!
Tema [17]

Answer:

21 in^{2}

Step-by-step explanation:

The square in the middle has a length and width of 3, so multiply. <u>9</u>.

All of the triangles have a base of 3 and a height of 2. The area equation for triangles is

A=bh\frac{1}{2}

So base*height is 6. Divide that by 2 or multiply by 1/2.

You get 3. There are 4 triangles, so multiply <em>that</em> by 4. <u>12</u>.

Add 12 and 9 together, and you get:

21 in^{2}

I hope this helps!

6 0
2 years ago
if one tray can hold 12 loaves of bread and eat your I can hold 10 trays can a hundred twenty-five Loaves fit on one rack
tia_tia [17]
I believe the wording of the question is: If one tray can hold 12 loaves of bread and the rack can hold 10 trays, can a hundred and twenty-five loaves fit on one rack? 
Then the answer would be, no. 
12 x 10 = 120

6 0
2 years ago
Read 2 more answers
A polygon has vertices at (-1,1), (1,1), (1,-1) &amp; (-1,-1) what is the perimeter in units of the polygon
sukhopar [10]

Answer:

8

Step-by-step explanation:

5 0
2 years ago
How do you solve this absolute value equatuon? 4|x - 1| - 7 = -3
MatroZZZ [7]
4|x - 1| - 7 = -3    |add 7 to both sides

4|x - 1| = 4    |divide both sides by 4

|x - 1| = 1 ⇔ x - 1 = 1 or x - 1 = -1    |add 1 to both sides

x = 2 or x = 0

Answer: B.
3 0
3 years ago
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