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quester [9]
3 years ago
11

Nora owns a food truck that sells tacos and burritos. She sells each taco for 1 point

Mathematics
1 answer:
atroni [7]3 years ago
7 0
3.75t +8.25b(greater than or equal to) 420
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A 747 Airplane is 762 inches tall. How tall is it in feet
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Answer:

The answer is 63.5 feet :)

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Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?
Flura [38]

Answer:

The value to the given expression is 8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3

To find the value of the given expression:

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}

( By using the property ((\frac{a}{b})^m=\frac{a^m}{b^m} )

=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}

( By using the property (ab)^m=a^mb^m )

=\frac{(10^{12})(5^6)}{(10^9)(5^9)}

( By using the property (a^m)^n=a^{mn} )

=(10^{12})(5^6)(10^{-9})(5^{-9})

( By using the property \frac{1}{a^m}=a^{-m} )

=(10^{12-9})(5^{6-9}) (By using the property a^m.b^n=a^{m+n} )

=(10^3)(5^{-3})

=\frac{10^3}{5^3} ( By using the property a^{-m}=\frac{1}{a^m} )

=\frac{1000}{125}

=8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Therefore the value to the given expression is 8

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Is 8:10 equivalent to 9:12
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No they are not equal

Step-by-step explanation:

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Rich is tossing a normal quarter. He tosses the quarter 25 times and it lands on heads 5 times. If Rich tosses the quarter again
kotegsom [21]

Answer:

ss

Step-by-step explanation:

sss

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Round 5049 correct to 1 significant figure​
Step2247 [10]

5000

  • Addition (+) and subtraction (-) round by the least number of decimals.
  • Multiplication (* or ×) and division (/ or ÷) round by the least number of significant figures.
  • Logarithm (log, ln) uses the input's number of significant figures as the result's number of decimals.
  • Antilogarithm (n^x.y) uses the power's number of decimals (mantissa) as the result's number of significant figures.
  • Exponentiation (n^x) only rounds by the significant figures in the base.
  • To count trailing zeros, add a decimal point at the end (e.g. 1000.) or use scientific notation (e.g. 1.000 × 10^3 or 1.000e3).
  • Zeros have all their digits counted as significant (e.g. 0 = 1, 0.00 = 3).
  • Rounds when required, after parentheses, and on the final step.

<em>-</em><em> </em><em>BRAINLIEST </em><em>answerer</em><em> ❤️</em>

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