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BaLLatris [955]
3 years ago
5

A survey was conducted that asked 997 people how many books they had read in the past year. Results indicated that x overbar equ

als 13.2 books and sequels 18.9 books. Construct a 95 ​% confidence interval for the mean number of books people read. Interpret the interval.
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer:

The 95% confidence interval would be given by (12.03;14.37)    

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=13.2 represent the sample mean  

\mu population mean (variable of interest)

s=18.9 represent the sample standard deviation

n=997 represent the sample size  

2) Calculate the confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=997-1=996

Since the confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,996)".And we see that t_{\alpha/2}=1.96 and this value is exactly the same for the normal standard distribution and makes sense since the sample size is large enough to approximate the t distribution with the normal standard distribution.

Now we have everything in order to replace into formula (1):

13.2-1.96\frac{18.9}{\sqrt{997}}=12.03    

13.2+1.96\frac{18.9}{\sqrt{997}}=14.37

So on this case the 95% confidence interval would be given by (12.03;14.37)    

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