All categories

2 years ago

What is 4.8 as a mixed number

Mathematics

2 answers:

Alex Ar [27]2 years ago

6 0

4 and 8/10 but simplified it's 4 and 2/5

Mariulka [41]2 years ago

3 0

The answer would be 4 4/5

You might be interested in

HELP!! WILL GIVE BRAINLIEST!!!

otez555 [7]

Answer:

David needs 7-8 short term rentals monthly to match revenue from a lease. College students need long term housing so he should lease his home.

Step-by-step explanation:

8 0

2 years ago

What is 11.45 as a fraction

Viefleur [7K]

11.45

the 11 is ur whole number...it stays ur whole number
the 0.45 is ur fraction...and since the last number (5) is in the hundredths place, put it over 100
so u now have : 11 45/100 which reduces to 11 9/20 and if u need it in improper fraction form, it is 229/20

6 0

2 years ago

Read 2 more answers

16. Jason leaves Detroit at 2: 00 PM and drives at a constant speed west along I-94. He passes Ann Arbor, 40 mi from Detroit, at

Vesna [10]

Answer:

at 2: 00 PM constant speed may 4:00 constant speed

Step-by-step explanation:

makatulong po ba

5 0

1 year ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

2 years ago

A candy manufacturer is interested in the distribution of colors in each of its packages of candy sold. The manufacturer randoml

Otrada [13]

Answer:

Option B

Step-by-step explanation:

Given that a candy manufacturer is interested in the distribution of colors in each of its packages of candy sold. The manufacturer randomly sample packages from multiple batches at one factory.

Because he resorts to only one factory, there may be bias in the sample. Other factories may have different processes of the settings and also if a diversified sample is taken then it is likely to represent the whole population, and hence results would be more accurate

Option A is incorrect since only one factory was done

C and D are not selected because one factory result cannot be generalised to all other factors in the same country or outside.

So answer would be

B) No, because the other factories may have different processes or the settings

7 0

2 years ago