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GaryK [48]
3 years ago
14

What is 16,473 to the nearest hundred

Mathematics
1 answer:
Verizon [17]3 years ago
4 0
The number "4" is in the hundreds place. To the right is 7, and since it's greater than five it rounds up. So 16,473 to the nearest hundred is 16,500. Hope this helped!
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lianna [129]

Answer:

The person that answered at the top is a legend!! The picture below is just proof that he/she is right!! :)

Step-by-step explanation:

9514 1404 393

 see attached Starting with the original function, swap the variables x and y, then solve for y. The resulting function is the inverse of the original function.

i hope this help's pleazz dont report me okay

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2 years ago
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One night a theater sold 186 movie tickets. an adults ticket cost $14, and a childs costs $10. in all, $2148 was taken in. How m
inna [77]

Answer:

72 adult tickets were sold and 114 child tickets were sold.

Step-by-step explanation:

x+y=186, 14x=10y=2148

x=186-y

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3 years ago
Last question , thanks!!! so much!!!!:)))))
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Answer:

1,3

Step-by-step explanation:

1,3 is were they intersect, go sideways 1, and up 3

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Lauryn wants to analyze the weights of
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Functionally important traits in animals tend to vary little from one individual to the next within populations, possibly becaus
const2013 [10]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X:  Ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloth.

The researcher's claim is that the ratio of the SC of the sloths is more variable than in other animal species that are more active.

For more active species the standard deviation of the ratio is σ= 0.09

1)

To calculate the sample standard deviation you have to calculate the sample variance first:

S^2= \frac{1}{n-1} [sumX^2-\frac{(sumX)^2}{n} ]

n=7; ∑X= 8.91; ∑X²= 11.8599

S^2= \frac{1}{6} [11.5899-\frac{(8.91)^2}{7} ]= 0.0287= 0.029

S= √S²= √0.029= 0.169≅ 0.17

The sample standard deviation of the ratio is 0.17

2)

The parameter of interest is the population standard deviation. To calculate a confidence interval for the standard deviation of a population you have to estimate the population variance first. Then calculate the square root of both limits of the interval for the variance to obtain the interval for the standard deviation.

The statistic to use is the Chi-Square and the formula for the interval is:

[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]

X^2_{n-1;\alpha /2}= X^2_{6; 0.025}= 1.2373

X^2_{n-1;1-\alpha /2}= X^2_{6; 0.975}= 14.449

[\frac{6*0.029}{14.449} ;\frac{6*0.029}{1.2373} ]\\

[0.0120; 0.1406]

Using a 95% confidence level you'd expect the interval [0.0120; 0.1406] to include the true value of the population variance of the ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloths.

Now you have to calculate the square root of each limit:

[√0.0120; √0.1406]

[0.1097; 0.3750]

Using a 95% confidence level you'd expect the interval [0.1097; 0.3750] to include the true value of the population standard deviation of the ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloths.

3)

As you can see the calculated interval doesn't include the value obtained for the other species.

I hope this helps!

5 0
3 years ago
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