All categories

2 years ago

A notebook costs $4.50 plus sales tax . After sales tax , the notebook is $4.86. What is the sales tax rate?

Mathematics

2 answers:

UkoKoshka [18]2 years ago

6 0

Answer:

Step-by-step explanation:

0.36/4.50=0.08=8%

Ipatiy [6.2K]2 years ago

6 0

The answer to your question is 8%

You might be interested in

An octagon has a perimeter of 28 units. What is the perimeter of the image of the octagon after the translation (x,y) → (x-7,y+

kow [346]

Answer:

https://www.caverna.k12.ky.us/userfiles/110/Classes/7142//userfiles/110/my%20files/study%20guide%20answer%20key%20(1).pdf?id=4059

Step-by-step explanation:

copy and past this pdf

6 0

3 years ago

I need the answer fast pls

igomit [66]

Answer:

its a statistical question

Step-by-step explanation:

Statistics is a branch of mathematics that deals with collecting, analyzing, and interpreting information

6 0

2 years ago

Read 2 more answers

Find the measure of side b.

malfutka [58]

I think it’s 236.8 correct me if I’m wrong?

7 0

2 years ago

A dress shop bought material for £4.65 a metre and sold it for £6.90 a metre. How much

stepladder [879]

Answer:

£67.50

Step-by-step explanation:

On each metre of material, the shop makes a profit of ...

£6.90 -4.65 = £2.25

So, for 30 metres, the profit will total ...

30 × £2.25 = £67.50

A profit of £67.50 would be made on a 30-metre roll of material.

8 0

3 years ago

The probability density function of the time you arrive at a terminal (in minutes after 8:00 A.M.) is f(x) = 0.1 exp(−0.1x) for

Blababa [14]

$f_X(x)=\begin{cases}0.1e^{-0.1x}&\text{for }x>0\\0&\text{otherwise}\end{cases}$

a. 9:00 AM is the 60 minute mark:

$f_X(60)=0.1e^{-0.1\cdot60}\approx0.000248$

b. 8:15 and 8:30 AM are the 15 and 30 minute marks, respectively. The probability of arriving at some point between them is

$\displaystyle\int_{15}^{30}f_X(x)\,\mathrm dx\approx0.173$

c. The probability of arriving on any given day before 8:40 AM (the 40 minute mark) is

$\displaystyle\int_0^{40}f_X(x)\,\mathrm dx\approx0.982$

The probability of doing so for at least 2 of 5 days is

$\displaystyle\sum_{n=2}^5\binom5n(0.982)^n(1-0.982)^{5-n}\approx1$

i.e. you're virtually guaranteed to arrive within the first 40 minutes at least twice.

d. Integrate the PDF to obtain the CDF:

$F_X(x)=\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=\begin{cases}0&\text{for }x$

Then the desired probability is

$F_X(30)-F_X(15)\approx0.950-0.777=0.173$

7 0

3 years ago