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3 years ago

What are the steps to solving this limit?

Mathematics

2 answers:

patriot [66]3 years ago

6 0

Answer:

lim(x---->0) = -5

Step-by-step explanation:

first: sin(x-π/2)= -cosx

so the equation will be :

lim(x---->0) = [-6cos(ax)-1}/cosx

solve :

lim(x---->0) = [-(6cos(a(0))-1}/cos(0)

cos0=1

lim(x---->0)=(-(6(1)-1)/1

lim(x---->0)=-6+1/1

lim(x---->0)=-5

Aleks [24]3 years ago

5 0

-5 I hope this helps u

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A coin is thrown at random into the red triangle below.

Yakvenalex [24]

it is impossible

Step-by-step explanation:

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2 years ago

-7 1/3 > -11 1/4 <br> true or false?!?

Varvara68 [4.7K]

Answer:

False

Step-by-step explanation:

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3 years ago

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What is the equation in point slope form of the line that passes through the point (−1, −3) and has a slope of 4?

lutik1710 [3]

I agree with the second answer. Was this correct?

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3 years ago

How do you divide 7.06 by 0.353?

Rama09 [41]

Well it is really hard to divide decimals and it will be good if you had a calculator, but if not you can always convert the decimal to a fraction, you do this by getting your numbers and convert them by the place where your last digit is at for example the first one is in a value of a hundred this means that it would be 6/100, I automatically jumped to this because my first digit after the point is a 0 but if it wasn't I had to do the whole problem, but don't worry I will explain in the next decimal. Like I was saying this now is 6/100 this can be simplified by 2 and we would get 3/50, now you might be wondering what do I do with the 7 that is before thepoint, well that is called a whole number so this fraction now is going to be a mixed fraction, this would look like 7 3/50... Now lets check t he next one this one is in a value of a thousand but since we have number bigger than 1 lets check how to do this, well you will first put your numbers with your values 3/10(because it is in the tenth power) 5/100 and 3/1000 now we haev to find a common factor for the last digits this would be 1000 so now multiply your other 2 numbers that are not 1000 by the number taht will make it get to 1000 for the first one it will be 100 this will give you 300/1000, the second one will be multiplied by 10 this will give you 50/1000, and the last one is multiplied by 1 so it will be the same thing now add all of these numbers 300/1000+50/1000+3/1000 (note that your bottom number will stay the same) this will give you 353/1000 (see how your top number is the same as the numbers after the point in your decimal, it is always like this but I wanted to explain where you got that from) now simplify your fraction, your fraction can't be simplified. now you have your 2 decimals as fractions, these are 7 3/50 divided by 353/1000 you first have to convert your mixed number to a normal fraction, you do this by multiplying your bottom number by your whole number and then addign the top this will give you 353/50 now you have to find a comon factor again for you rnew 2 bottom numbers, this number will again be 1000, now what do you multiply by 50 to get 1000?? well it will be 20 so multiply your bottom and top number by 20 to get 7060/1000 now add that to 353/1000 (again your bottom number stays the same) to get 7413/1000, you can always simplify it if you want to get another fraction, but if you want a decimal just divide it to get 7.413

Hope this helps

7 0

2 years ago

Read 2 more answers

If the volume of a box is 2x3 + 4x2 − 30xwhich of the dimensions are possible with the given x-value?

Kipish [7]

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is $2 x^{3} + 4 x^{2} -30x$ .

Step-by-step explanation:

The given is,

$2 x^{3} + 4 x^{2} -30x$ ................................(1)

Step:1

Check for option A,

x = 1, dimensions 8 by 9 by 1

From the equation (1),

Volume = $2 (1^{3}) + 4 (1^{2} )-30(1)$

$=2+4-30$ = -24...................(2)

From the dimensions,

Volume = ( 8 × 9 × 1 )

= 72............................................(3)

From equation (2) and (3)

-24 ≠ 72

So, X=1; dimensions 8 by 9 by 1 is not possible.

Check for option B,

x = 1, dimensions 2 by 5 by 3

From the equation (1),

Volume = $2 (1^{3}) + 4 (1^{2} )-30(1)$

$=2+4-30$ = -24...................(4)

From the dimensions,

Volume = ( 2 × 5 × 3 )

= 30.........................................(5)

From equation (4) and (5)

-24 ≠ 30

So, X=1; dimensions 2 by 5 by 3 is not possible.

Check for option C,

x = 4, dimensions 2 by 5 by 3

From the equation (1),

Volume = $2 (4^{3}) + 4 (4^{2} )-30(4)$

$=2(64)+4(16)-30(4)$

$= 128+64-120$

= 72.............................................(6)

From the dimensions,

Volume = ( 2 × 5 × 3 )

= 30............................................(7)

From equation (6) and (7)

72 ≠ 30

So, X=4; dimensions 2 by 5 by 3 is not possible.

Check for option C,

x = 4, dimensions 8 by 9 by 1

From the equation (1),

Volume = $2 (4^{3}) + 4 (4^{2} )-30(4)$

$=2(64)+4(16)-30(4)$

$= 128+64-120$

= 72............................................(8)

From the dimensions,

Volume = ( 8 × 9 × 1 )

= 72............................................(9)

From equation (8) and (9)

72 = 72

So, X=4; dimensions 8 by 9 by 3 is possible.

Result:

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is $2 x^{3} + 4 x^{2} -30x$ .

4 0

3 years ago