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3 years ago

What are the steps to solving this limit?

Mathematics

2 answers:

patriot [66]3 years ago

6 0

Answer:

lim(x---->0) = -5

Step-by-step explanation:

first: sin(x-π/2)= -cosx

so the equation will be :

lim(x---->0) = [-6cos(ax)-1}/cosx

solve :

lim(x---->0) = [-(6cos(a(0))-1}/cos(0)

cos0=1

lim(x---->0)=(-(6(1)-1)/1

lim(x---->0)=-6+1/1

lim(x---->0)=-5

Aleks [24]3 years ago

5 0

-5 I hope this helps u

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____ [38]

This is pretty weird: ax+ b > c is equivalent to ax + b > 0, for instance. c might always be chosen as zero, or b, or any value!

280x <= 348.76, or -280x + 348.76 >= 0,

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3 years ago

Please help... I really need this.

valentinak56 [21]

Answer:

$\frac{4x^3-3x^2+5x+6}{x+6}=4x^2-27x+167-\frac{996}{x+6}$

Step-by-step explanation:

The division problem given to us is $(4x^3-3x^2+5x+6)\div (x+6)$ .

To perform the synthetic division, we write out the coefficient of the polynomial. We set the linear factor to zero and solve for x, this becomes our divisor. That is $x+6=0\implies x=-6$ .

We carry out the synthetic division as shown in the attachment.

The result of the synthetic division is 4 -27 167 -996

The first three terms are the coefficients of the quotient and the last term is the remainder.

Therefore the quotient is $q(x)=4x^2-27x+167$ and the remainder is $r(x)=-996$ .

The dividend, the quotient and the divisor are written as

$\frac{4x^3-3x^2+5x+6}{x+6}=4x^2-27x+167-\frac{996}{x+6}$

The correct answer is A

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Amiraneli [1.4K]

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