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Anton [14]
3 years ago
14

28 people ordered dessert

Mathematics
2 answers:
MrRissso [65]3 years ago
8 0

Answer:

8 people ordered ice cream

Step-by-step explanation:

28/7=4

4x2=8

SVEN [57.7K]3 years ago
6 0

Answer:

20 people

Step-by-step explanation:

The first step is to find out how many people are in 1/7 of the group. To do this, we divide 28÷7, and our answer is 4.

28÷7=4

Our next step is to find out how many people are in 2/7 of the group. We would double the 4, since 1/7 doubled is 2/7, and get 8.

4 x 2= 8

Now we know that 8 people ordered ice cream. To find the number of people who ordered the special, we subtract 8 from 28.

28-8= 20

Therefore, 20 people ordered the special. Hope this helps!

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Find the value of x is y=0
Drupady [299]

Answer:

01= x

Step-by-step explanatiothis is the answer

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4x/5 - 3x/7 = 4x/7 + 5x/7 can anyone please help with explanation...​
kirill115 [55]

Answer: x=0

Step-by-step explanation:

Multiply both sides of the equation by 35, the least common multiple of 5,7.

7×4x−5×3x=5×4x+5×5x

Multiply 7 and 4 to get 28.

28x−5×3x=5×4x+5×5x

Multiply −5 and 3 to get −15.

28x−15x=5×4x+5×5x

Combine 28x and −15x to get 13x.

13x=20x+25x

Combine 20x and 25x to get 45x.

13x=45x

Subtract 45x from both sides

13x−45x=0

Combine 13x and −45x to get −32x

−32x=0

Product of two numbers is equal to 0 if at least one of them is 0. Since −32 is not equal to 0, x must be equal to 0.

X=0

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3 years ago
Which of the following mapping diagrams does not represent a function?
Tamiku [17]

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Step-by-step explanation:

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PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS
Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\

With respect to reference angle A, we have:

  • opposite side = a = 4
  • adjacent side = b = \sqrt{33}
  • hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\

Then cosine which is adjacent over hypotenuse

\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\

Tangent is the ratio of opposite over adjacent

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

  • cosecant, abbreviated as csc, is the reciprocal of sine
  • secant, abbreviated as sec, is the reciprocal of cosine
  • cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{  ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

------------------------------------------------------

Summary:

The missing side is b = \sqrt{33}

The 6 trig functions have these results

\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0
1 year ago
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