In this circle we have major arc RQ which is the really big one measuring 40x, and we have minor arc RQ, which is what we are looking for. Minor arc RQ is double the measure of the angle that intercepts it. That means that minor arc RQ is 2(12x-12), which is 24x - 24. The measure of the outside of any circle will always and forever be 360 degrees; therefore, 40x + 24x - 24 = 360. Combining like terms gives us 64x = 384 and x = 6. Now sub in that 6 for the x in the angle 12x - 12 to get that that angle measures 12(6)-12 = 60. Again, the angle is half the measure of the arc it intercepts, so minor arc RQ is 120 degrees, third choice down.
Answer:
130°
Step-by-step explanation:
All the interior angles should add up to 540 degrees because it's a pentagon
∠T ≅∠S, so ∠T is also 115°
∠P and ∠R are both 90°
Add everything up and solve for ∠Q:
115 + 115 + 90 + 90 + m∠Q = 540
410 + m∠Q = 540
m∠Q = 130°
Answer:
I had this question, photomath works.
Step-by-step explanation:
Because this is a right angle triangle, we can use the Pythagorean theorem to find the missing leg.
The Pythagorean theorem is this:
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The Pythagorean theorem tells us if you square both the legs then add them up together, you will get the length of the hypotenuse squared.
We know one leg is 24 and the hypotenuse is 26. Plug them into the equation.
24^2 + b^2 = 26^2
Solve for b.
24^2 + b^2 = 26^2
576 + b^2 = 26^2
576 + b^2 = 676
b^2 = 100
Take the square root of both sides.
b = 10
So, the other leg of the triangle is 10 units long.
Answer:
its A -6r+6
Step-by-step explanation:
ur very welcome