Six tenths as a decimal
2 answers:
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Answer:
1)4
2)28
3)18.3
4)38.5
5)22.5
6)19.25
7)25.5
8)69.666
9)6.5
10)22.666
Step-by-step explanation:
- To do this first you should convert the mix numbers into inproper fractions and then solve.
1)8/5*5/2=4
2)21/5*20/3=7*4
=28
3)33/4*20/9=11*5/3
=55/3
=18.33...
=18.3
4)35/6*33/5=7*11/2
=77/2
=38.5
5)22/8*90/11=45/2
=22.5
6)11/3*21/4=11*7/4
=77/4
=19.25
7)34/5*15/4=34*3/4
=25.5
8)22/3*57/6=11*19/3
=209/3
=69.666
9)39/8*4/3=13/2
=6.5
10)17/2*8/3=17*4/3
=68/3
=22.666
<em>Hope you got this</em>
<em>If you have any doubt please ask me</em>
<em>If you need this in fraction form just check the attachment</em>
Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case :
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>
Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get
Hence amount owed at the end of 1 year is 3640