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3 years ago

If f (x) = StartRoot x minus 3 EndRoot, which inequality can be used to find the domain of f(x)?

Mathematics

2 answers:

Maurinko [17]3 years ago

5 0

Answer:

$x - 3 \geqslant 0$

Step-by-step explanation:

The given square root function is

$f(x) = \sqrt{x - 3}$

The domain refers to all values of x that will make this square root function defined.

We know that negative values will not be defined for the square root function therefore the expression under the root should be greater or equal to zero.

Hence the inequality that can be used to find the domain of f(x) is

$x - 3 \geqslant 0$

luda_lava [24]3 years ago

4 0

Answer:B on edge

Step-by-step explanation: no cap

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1) write the equation of the

Helen [10]

Answer:

y=3/2x-2

Step-by-step explanation:

Find the slope first:

$m=\frac{y_{2-y_{1} } }{x_{2}-x_{1} } =\frac{1-(-2)}{2-0}=\frac{3}{2}$

Then solve for y-intercept:

$y=\frac{3}{2}x+b\\-2=\frac{3}{2}(0)+b\\-2=b$

Now, write out your complete equation:

y=3/2x-2

6 0

3 years ago

Please help ASAP!!! Will give brainlist :)

Furkat [3]

Answer:

A': (2,1)

B': (5,3)

C': (4,-1)

x -----> x + 1

y -----> y - 2

4 0

3 years ago

Please need help on this

Trava [24]

Answer:

The perimeter of a shape is the sum of the measurements of all sides. Since a rectangle have equal lengths and widths, you can just add the numbers twice.

So, 15 + 15 + 8 + 8. So the perimeter is 46 cm.

7 0

3 years ago

Read 2 more answers

Find me equation of the circle with Center at ( 3, - 2) and radius of 3

blondinia [14]

The equation of a circle with center $(x_0,y_0)$ and radius $r$ is

$(x-x_0)^2+(y-y_0)^2=r^2$

In your case,

$x_0=3,\quad y_0=-2,\quad r=3$

Plug these values into the generic formula and you'll get your equation.

5 0

3 years ago

Use the relative frequency approach to estimate the probability of the event. In a certain class of students, there are 8 boys f

In-s [12.5K]

Answer:

$P\text{Student will be from Kenilworth}\approx 0.256$

Step-by-step explanation:

We have been given that that there are 8 boys from Wilmette, 5 girls from Kenilworth, 9 girls from Wilmette, 5 boys from Glencoe, 5 boys from Kenilworth and 7 girls from Glenoce.

The total number of students from Kenilworth is 5 boys plus 5 girls that is 10 students.

The total number of students in the class would be $8+5+9+5+5+7=39$

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

$P\text{Student will be from Kenilworth}=\frac{\text{Number of student from Kenilworth}}{\text{Total number of students}}$

$P\text{Student will be from Kenilworth}=\frac{10}{39}$

$P\text{Student will be from Kenilworth}=0.2564102564$

$P\text{Student will be from Kenilworth}\approx 0.256$

Therefore, the probability, that the student will be from Kenilworth, is approximately 0.256.

7 0

3 years ago