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3 years ago

What is a like term?

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

8 0

Answer:

A like term is are terms that have the same variables or powers.

ad-work [718]3 years ago

4 0

Answer:

Like terms" are terms whose variables (and their exponents such as the 2 in x2) are the same. In other words, terms that are "like" each other.

Step-by-step explanation:

You might be interested in

A construction crew must build 4 miles of road in one week. On Monday, they build 12 mile of road. On Tuesday, they build 13 mil

Julli [10]

$\frac{19}{6}$ many more miles of road are left to build .

<u>Step-by-step explanation:</u>

Here we have , A construction crew must build 4 miles of road in one week. On Monday, they build 1/2 mile of road. On Tuesday, they build 1/3 mile of road. We need to find that How many more miles of road are left to build . Let's find out:

On Monday, they build 1/2 mile of road.
On Tuesday, they build 1/3 mile of road.

Let Miles of road left to build is x So,

⇒ $\frac{1}{2} +\frac{1}{3} +x = 4$

⇒ $x = 4 - (\frac{1}{2} +\frac{1}{3})$

⇒ $x = 4 - (\frac{1(3)+1(2)}{6} )$

⇒ $x = 4 - (\frac{5}{6} )$

⇒ $x = (\frac{4(6)-5}{6} )$

⇒ $x = \frac{24-5}{6}$

⇒ $x = \frac{19}{6}$

Therefore, $\frac{19}{6}$ many more miles of road are left to build .

5 0

3 years ago

Read 2 more answers

65.877 rounded to the nearest 10th

Kitty [74]

The answer is 65.9 because the place right after the decimal is the tenths place

5 0

3 years ago

Item 1

Ann [662]

Answer:

look at the attachment

Step-by-step explanation:

hope it helps!

6 0

3 years ago

Read 2 more answers

See attached picture, is there a way to enter equations or algebraic symbols?

coldgirl [10]

SOLUTIONS

Solve a given equations or algebraic symbols?

$\begin{gathered} f(x)=x^2+2x \\ g(x)=1-x^2 \end{gathered}$

(A)

$\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}$

(B)

$\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}$

(C)

$\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}$

(D)

$\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}$

5 0

1 year ago

Pls help me I know this is easy I’m just not smart

skelet666 [1.2K]

Answer:

Step-by-step explanation:

Given :

5c+cd where, $C=\frac{1}{5}$ and d=15

Now,

5× $\frac{1}{5} +\frac{1}{5} (15)$

=1+3

Answer is 4

3 0

3 years ago