648 is the three-digit positive integers have three different digits
According to the statement
we have given that there are three positive digit number are formed with three distinct digits.
And we have to find that the how many words are formed with distinct numbers.
So, to solve this type of problem the Combination formula is best.
Because it provides the all possibilities that from how many ways numbers are formed.
So, from a combination formula
here we take 9 two times because first time when we let a number then remaining numbers are 9. and second time remaining numbers are also 9 because we let the distinct number but for third number there will be a probability that choosing number will be same.
So, Three digit positive number become from 9*9*8 =648
So, 648 is the three-digit positive integers have three different digits.
Learn more about COMBINATION here brainly.com/question/4658834
#SPJ1
Answer:
0
Step-by-step explanation:
evaluate 10 + (8÷4) - 12
Step-by-step explanation:
bsbdbxbshzb jdjxhdjzbe
Answer:
D an = 9 + 7(n-1)
Step-by-step explanation:
In the question, Max has 9 logs in the first load. But, after the seventh load he has a total of 51 logs. So the n would be your logs in the stack, which is 51. And since there is a total of 51 logs after the seventh load. It would be 9 plus 7 in parenthesis of 51 minus one, which is 50. So 50 times 7 comes down to 350 plus nine which comes down to a total of 359.
