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emmasim [6.3K]
3 years ago
13

Solve using linear combination 4x+y=5 3x+y=3

Mathematics
2 answers:
Phantasy [73]3 years ago
5 0
X= 2 , y= -3 
You have to multiply the second equation by a negative and the you'll get,        -3x-y=-3. the y's cancel out and then you combine the x's and the 5 and the 3 and then x=2 and then you pick one of the two equations and sub in the x and solve for y. 
vagabundo [1.1K]3 years ago
4 0
X=2 y=3



think this could be it not 100% tough sorry















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Find the value of h(-67) for the function below.
Lelu [443]

Answer:

D. 3,158

Step-by-step explanation:

h(-67) means to plug the x in h(x)=-49x-125 into the function as -67

The function will then be:

h(-67)=-49(-67)-125

Multiply -49 and -67

h(-67)=3283-125

subtract

h(-67)=3158

so the answer is D

Hope this helps!  

4 0
3 years ago
Find the 6th term of the expansion of (2p - 3q)11. a. -7,185,024p4q7 c. -7,185p4q7 b. -7,185,024p6q5 d. -7,185p6q5
bezimeni [28]
\bf (2p-3q)^{11}\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2p)^{11}(-3q)^0\\
2&+11&(2p)^{10}(-3q)^1\\
3&+55&(2p)^9(-3q)^2\\
4&+165&(2p)^8(-3q)^3\\
5&+330&(2p)^7(-3q)^4\\
6&+462&(2p)^6(-3q)^5
\end{array}

the coefficient for the first term is 1, the next is 11 and so on... now, notice, the elements of the binomial, the 1st element starts off with 11, and every term it goes down by 1, the 2nd element starts off at 0, and goes up by 1 in each term.

now, to get the next coefficient, you simply, "get the product of the current coefficient and the exponent of the 1st element, and divide that by the exponent of the 2nd element in the next term".

for example, how did we get 165 for the 4th term.... well  (55*9)/3

how did we get 462 for the 6th term? well (330*7)/5.

and then you can just expand it from there.
8 0
3 years ago
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mariarad [96]

Let

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we know that

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therefore

<u>the answer is</u>

The domain is all real numbers 0 through 30

4 0
3 years ago
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Mamont248 [21]
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Answer:

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Step-by-step explanation:

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