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fredd [130]
3 years ago
10

3) A data set has 11 numbers in it. Each number is a whole number and there are no repeats. The bottom 2 values of the data set

are 2, 3. The top 2 values of the data set are 22, 23. What is the largest POSSIBLE value for the interquartile range? A) 16 B) 17 C) 18 D) 19
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

C) 18 is your answer

Hope this brings you luck ^o^ ^_^

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If there are 2,000 females and 2,000 males enrolled at a college and four different students are randomly selected to receive a
DENIUS [597]

Answer:

500

Step-by-step explanation:

you just divide 2000 by 4 and get 500

6 0
3 years ago
11
drek231 [11]

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sub to graec franz

Step-by-step explanation:

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2 years ago
Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.
agasfer [191]

Answer:

Class Boundary = 1 between the sixth and seventh classes.

Step-by-step explanation:

              Lengths (mm)                   Frequency

1.                  140 - 143                                  1

2.                 144 - 147                                 16

3.                 148 - 151                                 71

4.                 152 - 155                              108

5.                 156 - 159                               83

6.                 160 - 163                                18

7.                  164 - 167                                 3

The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.

Therefore the class boundary between the sixth and seventh classes

= 164 - 163  = 1

Therefore Class Boundary = 1.

It can be seen that class boundary for the frequency distribution is 1.

If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.

Therefore, Class width,

w = lower limit of second class - lower limit of first class

   = 144 - 140

   = 4

7 0
3 years ago
11-30x+24. what is this answer ​
zavuch27 [327]

Answer:

-30x+35

Step-by-step explanation:

Add 11 and 24

3 0
3 years ago
PLEASE HELP!
Anettt [7]

Answer: 2,3 and 4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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