From F.S 1, consider this series : 8, 1, 8, 8, 64, 64*8.
Again, consider the series 2, 1/4, 1/2, 1/8, 1/16, 1/(8*16). Clearly, the difference of the 6th and the 3rd term is different for them. Insufficient.
<span>From F.S 2, let the series be </span><span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span></span><span>. Now we know that </span><span><span>a<span>b2</span>=1</span><span>a<span>b2</span>=1</span></span>. The required difference =<span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span></span><span>= 0.Sufficient.</span>
Answer:
I think is B.
Step-by-step explanation:
hope its help
Answer:
give my about ten mins i got to finish this final exam for math seg 1
Step-by-step explanation:
Any statement as answers choice?
The number of infected banana plants with a rate of 8% will be in 8 years is 848.
<h3>What is exponential growth or decay function?</h3>
Consider the function:
y = a(1 + r)ˣ
where x is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.
A blight is spreading on a banana plantation. Currently, 458 banana plants are infected.
If the disease is spreading at a rate of 8% each year.
Then the number of the plants that will be infected in 8 years.
Then the exponential function is given as
y = 458(1.08)ˣ
At x = 8, then we have
y = 458(1.08)⁸
y = 458 x 1.851
y = 847.73
y ≅ 848
Learn more about exponential growth and decay here:
brainly.com/question/2193820
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