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nignag [31]
3 years ago
5

What is the value of n so that the equation has one solution? 2x squared-4x+n=0

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
8 0

The answer is 2.

Hope this helps!

GrogVix [38]3 years ago
4 0

Answer:

2

Step-by-step explanation:

2x^2 - 4x + n = 0 has only one solution when it can be represented as:

a(x-b)^2 = 0

Let us begin by factoring  out the 2 we are left with:

2(x^2 - 2x + m) = 0 where 2 * m = n

Now x^2- 2x + m can be represented as (x-a)(x-b) where a + b = 2 and m = a * b

We want a = b and a + b = 2 so a = b = 1

Hence m = 1

So 2(x^2 - 2x + 1) = 0

So 2x^2 - 4x + 2 = 0

Hence n = 2

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Nady [450]

Answer:

m = 7

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2m + -4 = 10

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