B. 5 you subtract -4-1 divided by 1-2 and so the negatives cancel out and the answer is 5/1 or 5
The line segment AB with endpoints (-10,0) and (6,8). The equation of the line segment is x-2y+10=0.
Given that,
The line segment AB with endpoints (-10,0) and (6,8).
We have to find the equation of the line segment.
The equation of the line formula is y-y₁=m(x-x₁).
Here we don't know the m value that is nothing but slope of the line.
First we have to find the slope of the line segment.
Slope of the line m=![\frac{y_{2} -y_{1} }{x_{2} -x_{1} }](https://tex.z-dn.net/?f=%5Cfrac%7By_%7B2%7D%20-y_%7B1%7D%20%7D%7Bx_%7B2%7D%20-x_%7B1%7D%20%7D)
m=(8-0)/(6+10)
m=8/16
m=1/2
Now,
We know the equation of line is y-y₁=m(x-x₁)
y-0=1/2(x+10)
2y=x+10
x-2y+10=0
Therefore, The equation of the line segment is x-2y+10=0.
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Answer:
y=2x-7
Step-by-step explanation:
y-y1=m(x-x1)
y-3=2(x-5)
y=2x-10+3
y=2x-7
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Answer:
4.35
Step-by-step explanation:
The expected value can be defined as:
where x_i = the payout, and p_i = the probability of it occurring.
This gives us the expression: ![(1 * 0.35) + (2 * 0.2) + (5 * 0.1) + (8 * 0.2) + (10 * 0.15) = 0.35 + 0.4 + 0.5 + 1.6 + 1.5 = 4.35](https://tex.z-dn.net/?f=%281%20%2A%200.35%29%20%2B%20%282%20%2A%200.2%29%20%2B%20%285%20%2A%200.1%29%20%2B%20%288%20%2A%200.2%29%20%2B%20%2810%20%2A%200.15%29%20%3D%200.35%20%2B%200.4%20%2B%200.5%20%2B%201.6%20%2B%201.5%20%3D%204.35)
So the expected payout is 4.35